How to check form submitted using Javascript and not PHP, then action PHP if submitted.

Hi,

I have a PHP form which refreshes  using Javascript as a way of passing values from one element of the form to another when the first element changes.  This presents a problem because I want to submit the form for action using a button, but I can't because the form has already autosubmitted as a way of refreshing its self to pass the element values.

In short I need to check that the form has been submitted without using the following PHP:
<input type="submit" name="submit" value="Update Client Record" />
<input type="hidden" name="submitted" value="TRUE" />
if (isset($_POST['submitted'])) { do somthing }


my code has the following elements:
-------------------------------------------------------------

echo '
<script language="JavaScript">

function autoSubmit()    <!-- This autoSubmit passes the value selected from the first element in the form to the second -->
{
    var formObject = document.forms[\'theForm\'];
    formObject.submit();
}    

function process(){
document.theForm.submit();    <!-- This is the bit I need to change-->
}


</script>';

If (...The form is submitted using the process() function run some PHP..)  <! And I need this bit -->

if (isset($_POST['movecat']))
{ // Form has been submitted.
      $movecat = $_POST['movecat'];
}

<form name="theForm" method="post">
<select name="movecat" onChange="autoSubmit();">........</select>
<select name="subcat" onChange="autoSubmit();">  
//....OPTION selected using $movecat variable....
</select>

<input type="button" value="Save Changes" onClick="process(); />

---------------------------------------------------------------------------

I need to change the way the process() funtion works.

something like:
If (theForm.submit == TRUE)
{ do my PHP }

I've no idea how to actually write this because it mixes javascript and php.


I hope this makes sense!!

Thanks for your help