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What is purpose of void return and arguments in memcpy() ?

naseeam asked
Last Modified: 2012-07-10
From 'C' book, here is memcpy() function:

void *memcpy(s, ct, n)

s is type     * void
ct is type    const void *

copy n characters from ct to s, return s

What is purpose of void arguments and void return type in this function?  Does memcpy() typecast   s   and   ct   to  * char ?  
How is  s   defined in calling code?  It's pointer to what?   What will calling code typecast memcpy() return value to ?
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