troubleshooting Question

What is purpose of void return and arguments in memcpy() ?

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naseeamFlag for United States of America asked on
CProgramming Languages-Other
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From 'C' book, here is memcpy() function:

void *memcpy(s, ct, n)

s is type     * void
ct is type    const void *

copy n characters from ct to s, return s


What is purpose of void arguments and void return type in this function?  Does memcpy() typecast   s   and   ct   to  * char ?  
How is  s   defined in calling code?  It's pointer to what?   What will calling code typecast memcpy() return value to ?
ASKER CERTIFIED SOLUTION
Zoppo

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