asked on

How to replace a string in Perl for the given string?

file://///dir1/dir2/dir3/dir4/dir5/dir6/dir7/dir8/dir9/dir10/dir11/dir12/20120816_1331_ReportDetails.html#/dir1/dir2/dir3/dir4/dir5/dir6/dir7/dir8/dir9/dir10/dir11/dir12/file.c

Open in new window

How can I replace the html file name in the string given above as the below:

file://///dir1/dir2/dir3/dir4/dir5/dir6/dir7/dir8/dir9/dir10/dir11/dir12/Test1_ReportDetails.html#/dir1/dir2/dir3/dir4/dir5/dir6/dir7/dir8/dir9/dir10/dir11/dir12/file.c

Open in new window

magento

In sed u can use like the below

In filename.txt file put the above text.

sed 's/original/replace/g' filename.txt

Open in new window

kaufmed

Try:

s#[^/]+_(ReportDetails.html)#Test1_$1#g

Open in new window

ASKER CERTIFIED SOLUTION

farzanj

membership

This solution is only available to members.

To access this solution, you must be a member of Experts Exchange.

Start Free Trial

Tolgar

ASKER

Original and replace are variables in my code. So I replaced single quotes with double quotes.

This is my line of code:

sed "s/$reportFileDetailsName/$newReportFileDetailsName/g" $reportFileName;

Open in new window

But got this error:

String found where operator expected at test.t line 225, near "sed "s/$reportFileDetailsName/$newReportFileDetailsName/g""
	(Do you need to predeclare sed?)
Scalar found where operator expected at test.t line 225, near ""s/$reportFileDetailsName/$newReportFileDetailsName/g" $reportFileName"
	(Missing operator before  $reportFileName?)
syntax error at test.t line 225, near "sed "s/$reportFileDetailsName/$newReportFileDetailsName/g""

Open in new window

SOLUTION

Lee Wadwell

membership

This solution is only available to members.

To access this solution, you must be a member of Experts Exchange.

Start Free Trial