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deanlee17

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Seaching a string

Hi all,

I need to search the following example string (strings will be varying lengths)...

England Garden Centre (EGC)

I need to extract just the name upto the first bracket and I guess we would need to trim incase there was a space betweem 'e' and '(' ?

Many Thanks,
Dean
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kaufmed
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Dim result As String = source.Substring(0, source.IndexOf("("c)).Trim()

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Hi Dean,

Here's an alternative method (with a probably more old-school coding style) which prevents an error if there is no "(" in the source string:

    Dim source = "England Garden Centre 123"
    Dim hit = InStr(source, "(")
    If hit = 0 Then hit = 999
    Dim result = Trim(Mid(source, 1, hit - 1))

If the source string could be longer than 999 chars, change the "999" to be some number longer than the maximum length it could be.
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Mike Tomlinson
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Nice work, IM!  Concise!
which prevents an error if there is no "(" in the source string:
Fine, if you're going to be a stickler about it  ; )

Dim result As String = source.Substring(0, If(source.IndexOf("("c) < 0, source.Length, source.IndexOf("("c))).Trim()

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you can also use this:

Dim result As String = System.Text.RegularExpressions.Regex.Replace(s, "\s*\(.*\)", "")

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Avatar of deanlee17
deanlee17

ASKER

Thanks for all the replies. However I was looking to extract the name and not the code, so...

England Garden Centre

and not EGC!

Also, technically, do i give the points to the correct right answer? Or the answer I like the most?

:)
Here:

System.Text.RegularExpressions.Regex.Replace(s, "\s*\(.*\)", "")

          s  = source string

\s*\(.*\)  = pattern

  \s* = here \s looks for whitespace characters and * represents zero or more occurances,
  \(  = '(' is expected character at this position and '\' is escape sequence.
  .* = mactes any character zero or more time
  \)  = ')' is expected character at this position and '\' is escape sequence.

Replace() method will replace this pattern to empty string.

e.g.,

Replace " (EGC)" from "England Garden Centre (EGC)" and leave "England Garden Centre"
if no matches found for text like " (EGC)" no replacement happens and simply text like "England Garden Centre" returns.

hope it helps!
I suggest you use Idle_Mind's, as it is the most consise/simple, IMHO.
    Dim result As String = source.Split("(")(0).Trim
I think that translates: Split the source into parts delimited by "(", then take the 1st part "part #(0)", trim leading/trailing spaces, and return that in result.

I expect all the answers are correct, but you might prefer some to others, so I suggest you split your points accordingly, giving more weight to the answer(s) which were most useful to you.  That's how I try to do it, anyway.
PS: Which of the answers are giving you the code ("EGC") instead of the name?
Sorry, my mistake, they arent, I switched some of my own code around :)
Well they all worked for me in VB.Net 2005 Express (though I haven't tested Shahan's or kaufmed's 2nd one).