Creating Sequential Letter Generator in vba. AA AB Revisted

Posted on 2012-08-24
Medium Priority
Last Modified: 2012-08-27
On my previous request on this subject I was provided a code solution that produced a string in the form of:

[Function ColXL(ByVal abc As String) As Long
' ** Covert Number to Letter Seq**
 ' * 108 to DD

abc = Trim(Replace(UCase(abc), "-", ""))
    Do While Len(abc)
        ColXL = ColXL * 26 + (Asc(abc) - vbKeyA + 1)
        abc = Mid(abc, 2)
End Function]

- - - - A thru ZZZZZ.   It  works great.   Now I need to popluate a listbox or combobox with values the user can select from.

For Example:
User need 3 Seqs ID's generated.  And the last Seq ID was "C"
User inputs "3" in a textbox and the list box would be populated with "D" ,  "E" , " F" to select from.

User inputs "4" and the Last Seq ID was  "AB"
the list box would be populated with "AC", "AD", "AE", "AF"

User inputs "2" and the Last Seq ID was  "AAAA"
the list box would be populated with "AAAB", "AAAC" etc.

This would occur all the way up to "ZZZZZ"

What's the best way to do this?  
Table were I update the recordset (rowsource)?


Question by:darkdell
  • 2
  • 2
LVL 40

Expert Comment

ID: 38330980
Test sample (with harfang's functions)

Author Comment

ID: 38337037

Thank you
That is very very close! But the listbox is including the orginal letter as well.

Like I stated, I need the "next" values indicated by the Q-ty values, excluding the current letter value.  That's why I'm having trouble (the loops).

So "A" with Q-ty 2 would give me "B","C"  not  "A" & "B"
LVL 74

Expert Comment

by:Jeffrey Coachman
ID: 38337552
Can you take a step back and explain the ultimate use for this system.

It seems like it is being used for interaction with Excel.
So perhaps an Excel based solution might be more fitting...?
LVL 40

Accepted Solution

als315 earned 2000 total points
ID: 38337907
No problems. Change function to:
Sub fill_list(ByVal Str As String, N As Integer)
Dim i As Integer
i = 0
With Me.MyListBox
  For i = .ListCount - 1 To 0 Step -1
        .RemoveItem i
  Next i
  For i = 0 To N - 1
        Str = XLcL(ColXL(Str) + 1)
        .AddItem Str
  Next i
End With
End Sub

Open in new window

String  .AddItem Str should be moved down

Author Comment

ID: 38338456
I was going to

Me.MyListBox.RemoveItem 0

at the end of the Sub fill_list code but your solution is much better thank you

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