biginteger print out in decimal for c

How is the biginteger stored?

Or check out how this guy did it and see if it works for you.
http://stackoverflow.com/questions/4735622/convert-large-hex-string-to-decimal-string

Converting Binary (or Hexadecimal) integers to decimal is straight forward but tedious.

But if you don't want to use a BIGINT library, you will have to write some subset of it yourself.

You have to choose the format of you output result, probably digit array or character string.
And you have to write functions for 2^n (or 16^n) as well as addition and multiplication.

the biginteger is stored in memory from lsb to msb bits in line the integer is from 2048 bit and up to 8192 bit i looking for a size independent method .

typedef struct
{
 	uint8_t  sign;
	uint16_t size;
	void *integer;
} bignum;

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void bn_init(bignum *nr, uint16_t size)
{
	nr->integer = malloc(size);
  	nr->size = size;
  	nr->sign = 0; //set positiov (0) 1= negativ
}

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function for hex print out

void bn_print_msb(bignum *nr)
{
	void *p_integer;
	void *p_end;
	p_integer = nr->integer;
	p_end = p_integer + nr->size;
	p_integer--;
	p_end--;
	while(p_end > p_integer)
		printf("%02X ", *((uint8_t *)p_end--));
	printf("\n");
}

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the solutions is c++