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iOS UITextView debug question

Posted on 2012-09-09
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Last Modified: 2012-09-17
I have a UITextView called textField.

I successfully set the textField.text property with a button and I can successfully read the value of textField.text and pass it to a function.

My question is how the heck to I display the value of textField.text in the debug window?

I have tried the following and neither works -
po textField.text
po [textField text]

Thanks,  Kevin.
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Question by:kevinvw1
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Hamidreza Vakilian earned 2000 total points
ID: 38381819
Please notice that you cant print out values of an objects property in gdb. E.g. you cant use po textView.text; instead you should use the second syntax: po [textView text]
Secondly you probably have set a breakpoint somewhere in your code and then you tried po [textView text] in gdb; if it's not working thats because textView is not declared in the scope the time you were executing gdb command.
Put a beakpoint on one line after where you have set textView.text in your code and try the gdb command again.
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