Want to protect your cyber security and still get fast solutions? Ask a secure question today.Go Premium

x
  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 482
  • Last Modified:

SQL, CASE

HI,

I have the following query

INSERT INTO #tbltest ([2008], [2009], [2010], [2011])
Select
            case when a.[2008] > b.[2008] then 'B' else 'b'  end as '2008',
            case when a.[2009] > b.[2009] then 'B' else 'b'  end as '2009',
            case when a.[2010] > b.[2010] then 'B' else 'b'  end as '2010',
            case when a.[2011] > b.[2011] then 'B' else ''b  end as '2011'
      From  #tbl1 a join #tbl2 b on a.UKey = b.UKey

in #tbl1 I have a record for 2008 = 0.80
in #tbl2 I have a record for 2008 = 0.70

I need to do some computation like this the first record (0.80) - second record (0.70) * 100

So when I do select * from #tbltest - the results are displayed like so

b (10)
B (5)

and so forth

please help

Thanks

R8VI
0
R8VI
Asked:
R8VI
1 Solution
 
David KrollCommented:
INSERT INTO #tbltest ([2008], [2009], [2010], [2011])
Select
            case
              when a.[2008] > b.[2008] then coalesce('B(', '') + coalesce(convert(varchar, (a.[2008] -   b.[2008]) * 100), '') + coalesce(')', '')
              else coalesce('b(', '') + coalesce(convert(varchar, (b.[2008] -   a.[2008]) * 100), '') + coalesce(')', '')   end as '2008',
            case
              when a.[2009] > b.[2009] then coalesce('B(', '') + coalesce(convert(varchar, (a.[2009] -   b.[2009) * 100), '') + coalesce(')', '')
              else coalesce('b(', '') + coalesce(convert(varchar, (b.[2009] -   a.[2009]) * 100), '') + coalesce(')', '')   end as '2009',
            case
              when a.[2010] > b.[2010] then coalesce('B(', '') + coalesce(convert(varchar, (a.[2010] -   b.[2010]) * 100), '') + coalesce(')', '')
              else coalesce('b(', '') + coalesce(convert(varchar, (b.[2010] -   a.[2010]) * 100), '') + coalesce(')', '')   end as '2010',
            case
              when a.[2011] > b.[2011] then coalesce('B(', '') + coalesce(convert(varchar, (a.[2011] -   b.[2011]) * 100), '') + coalesce(')', '')
              else coalesce('b(', '') + coalesce(convert(varchar, (b.[2011] -   a.[2011]) * 100), '') + coalesce(')', '')   end as '2011',
      From  #tbl1 a join #tbl2 b on a.UKey = b.UKey
0
 
LIONKINGCommented:
Will something like this work for you?

INSERT INTO #tbltest ([2008], [2009], [2010], [2011])
Select 
            case when a.[2008] > b.[2008] then 'B' else 'b'  end + ' (' + CONVERT(VARCHAR(6),(a.[2008]-b.[2008])*100) + ')' as '2008',
            case when a.[2009] > b.[2009] then 'B' else 'b'  end + ' (' + CONVERT(VARCHAR(6),(a.[2009]-b.[2009])*100) + ')' as '2009',
            case when a.[2010] > b.[2010] then 'B' else 'b'  end + ' (' + CONVERT(VARCHAR(6),(a.[2010]-b.[2010])*100) + ')' as '2010',
            case when a.[2011] > b.[2011] then 'B' else ''b  end + ' (' + CONVERT(VARCHAR(6),(a.[2011]-b.[2011])*100) + ')' as '2011'
      From  #tbl1 a join #tbl2 b on a.UKey = b.UKey

Open in new window

0

Featured Post

Concerto Cloud for Software Providers & ISVs

Can Concerto Cloud Services help you focus on evolving your application offerings, while delivering the best cloud experience to your customers? From DevOps to revenue models and customer support, the answer is yes!

Learn how Concerto can help you.

Tackle projects and never again get stuck behind a technical roadblock.
Join Now