MSSQL Select Sum where Sum>X Problem

trbbhm
trbbhm used Ask the Experts™
on
Will someone please show me how to structure the following SQL statement so that it will work?  I do not know how to write it so that it pulls data where the sum of sales is greater than X.

SELECT crm_Customer_Employee_Assignments.CustomerNum, crm_customerPurchaseRollup.custLevel, sum(custsls.priceextension) as sales  
FROM crm_Customer_Employee_Assignments
LEFT OUTER JOIN CUSTSLS ON crm_Customer_Employee_Assignments.CustomerNum=CUSTSLS.CustNum
LEFT OUTER JOIN crm_customerPurchaseRollup ON crm_Customer_Employee_Assignments.CustomerNum = crm_customerPurchaseRollup.trueCustNum
WHERE SUM(CUSTSLS.PRICEEXTENSION)>=1.23 group by customernum
Comment
Watch Question

Do more with

Expert Office
EXPERT OFFICE® is a registered trademark of EXPERTS EXCHANGE®
for aggregate conditions use HAVING, not WHERE.

Try this:

SELECT crm_Customer_Employee_Assignments.CustomerNum, crm_customerPurchaseRollup.custLevel, sum(custsls.priceextension) as sales  
FROM crm_Customer_Employee_Assignments
LEFT OUTER JOIN CUSTSLS ON crm_Customer_Employee_Assignments.CustomerNum=CUSTSLS.CustNum
LEFT OUTER JOIN crm_customerPurchaseRollup ON crm_Customer_Employee_Assignments.CustomerNum = crm_customerPurchaseRollup.trueCustNum
HAVING SUM(CUSTSLS.PRICEEXTENSION)>=1.23 group by customernum

Commented:
What about

SELECT crm_Customer_Employee_Assignments.CustomerNum, crm_customerPurchaseRollup.custLevel, sum(custsls.priceextension) as sales  
FROM crm_Customer_Employee_Assignments
LEFT OUTER JOIN CUSTSLS ON crm_Customer_Employee_Assignments.CustomerNum=CUSTSLS.CustNum
LEFT OUTER JOIN crm_customerPurchaseRollup ON crm_Customer_Employee_Assignments.CustomerNum = crm_customerPurchaseRollup.trueCustNum
WHERE sales>=1.23 group by customernum 

Open in new window

Do you mean you want to be able to use a variable called x?

DECLARE x double

SET x = 1.23

SELECT crm_Customer_Employee_Assignments.CustomerNum, crm_customerPurchaseRollup.custLevel, sum(custsls.priceextension) as sales  
FROM crm_Customer_Employee_Assignments
LEFT OUTER JOIN CUSTSLS ON crm_Customer_Employee_Assignments.CustomerNum=CUSTSLS.CustNum
LEFT OUTER JOIN crm_customerPurchaseRollup ON crm_Customer_Employee_Assignments.CustomerNum = crm_customerPurchaseRollup.trueCustNum
WHERE SUM(CUSTSLS.PRICEEXTENSION)>= x group by customernum
11/26 Forrester Webinar: Savings for Enterprise

How can your organization benefit from savings just by replacing your legacy backup solutions with Acronis' #CyberProtection? Join Forrester's Joe Branca and Ryan Davis from Acronis live as they explain how you can too.

Author

Commented:
@IENAXXX:  Invalid column name 'sales'.

@DKROLLCTN:  I was just using X as an example.  Say I wanted to pull data where sum(priceextension)> 450.64.  Your SQL example yielded the following error:  An aggregate may not appear in the WHERE clause unless it is in a subquery contained in a HAVING clause or a select list, and the column being aggregated is an outer reference.

Author

Commented:
@DANIELWILSON:  Incorrect syntax near the keyword 'group'.
Adjusting mine a little ...

SELECT crm_Customer_Employee_Assignments.CustomerNum, crm_customerPurchaseRollup.custLevel, sum(custsls.priceextension) as sales  
FROM crm_Customer_Employee_Assignments
LEFT OUTER JOIN CUSTSLS ON crm_Customer_Employee_Assignments.CustomerNum=CUSTSLS.CustNum
LEFT OUTER JOIN crm_customerPurchaseRollup ON crm_Customer_Employee_Assignments.CustomerNum = crm_customerPurchaseRollup.trueCustNum
 group by customernum ,crm_customerPurchaseRollup.custLevel
HAVING SUM(CUSTSLS.PRICEEXTENSION)>=1.23
SELECT crm_Customer_Employee_Assignments.CustomerNum, crm_customerPurchaseRollup.custLevel, sum(custsls.priceextension) as sales  
FROM crm_Customer_Employee_Assignments
LEFT OUTER JOIN CUSTSLS ON crm_Customer_Employee_Assignments.CustomerNum=CUSTSLS.CustNum
LEFT OUTER JOIN crm_customerPurchaseRollup ON crm_Customer_Employee_Assignments.CustomerNum = crm_customerPurchaseRollup.trueCustNum
group by customernum
HAVING SUM(CUSTSLS.PRICEEXTENSION)>= x

Author

Commented:
CHA-CHING!!!  Thank you!!!
Kyle AbrahamsSenior .Net Developer

Commented:
Edit:  Type after user answered question.

Author

Commented:
Who's Dan?  Is this DKrollCTN?  Is this about the points that were awarded?

DanielWilson posted a suggestion, which I tested, and accepted as solution before I saw the post by DKrollCTN (which is virtually identical to the post by DanielWilson).

I really don't mind sharing points, but the *first* solution was accepted.  If there is an argument about who gets the points, please take it up with management.

Do more with

Expert Office
Submit tech questions to Ask the Experts™ at any time to receive solutions, advice, and new ideas from leading industry professionals.

Start 7-Day Free Trial