Oracle SQL - filter records not used

Wilder1626
Wilder1626 used Ask the Experts™
on
Hello all

I have this SQL bellow that search for all TL_RATE used on LOAD and gives me a count on how many times they where used.

But i would like to do the opposite.

I would like to search all rates that was never used on a load. That, i really dont know what to start with.

Probably i just need to update the bellow SQL.

How can i do that?

Thanks again for your help.


Full SQL:
SELECT
    COUNT(DISTINCT BILL),
    LOAD.RATE_KEY,
    R.FROM_LOW_KEY_VALUE,
    R.FROM_HIGH_KEY_VALUE,
    R.FROM_COUNTRY,
    R.TO_LOW_KEY_VALUE,
    R.TO_HIGH_KEY_VALUE,
    R.TO_COUNTRY,
    LOAD.CARRIER_ID,
    TR.EFFECTIVE,
    TR.DATE_INVALID
FROM 
    LOAD, TL_RATE TR, LANE_RATE_NETWORK R
WHERE
    BEST_DEP > TO_DATE('20090830','YYYYMMDD')
    AND LOAD.RATE_KEY=TR.RATE_KEY
    AND TR.LANE_ID=R.ID
    GROUP BY LOAD.RATE_KEY,
    R.FROM_LOW_KEY_VALUE,
    R.FROM_HIGH_KEY_VALUE,
    R.FROM_COUNTRY,
    R.TO_LOW_KEY_VALUE,
    R.TO_HIGH_KEY_VALUE,
    R.TO_COUNTRY,
    LOAD.CARRIER_ID, 
    TR.EFFECTIVE,
    TR.DATE_INVALID
ORDER BY COUNT(DISTINCT BILL) DESC;

Open in new window

Comment
Watch Question

Do more with

Expert Office
EXPERT OFFICE® is a registered trademark of EXPERTS EXCHANGE®
View Solution Only
Senior Database Administrator
Commented:
Something like this should get you all the rates that aren't in load

select *
from tl_rate
where not (tl_rate.rate_key in (select load.rate_key from load))
Wilder1626

Author

Commented:
Hi sjwales

I think i'm missing one join somewhere cause i dont have any error and i done have any records also.

I think i have to also use this: AND TR.LANE_ID=R.ID
Wilder1626

Author

Commented:
I worked the code.

Let me test like this

SELECT   *
  FROM   TL_RATE
 WHERE   NOT (TL_RATE.RATE_KEY IN (SELECT   LOAD.RATE_KEY FROM LOAD)
              AND NOT (TL_RATE.LANE_ID IN
                             (SELECT   LANE_RATE_NETWORK.ID
                                FROM   LANE_RATE_NETWORK)))
         AND TL_RATE.DATE_INVALID >
               TO_DATE (TO_CHAR (SYSDATE, 'YYYYMMDD'), 'YYYYMMDD');

Open in new window

Wilder1626

Author

Commented:
Many thanks for your help

all good now

Do more with

Expert Office
Submit tech questions to Ask the Experts™ at any time to receive solutions, advice, and new ideas from leading industry professionals.

Start 7-Day Free Trial