VB6- Get counts of distinct value in MSHFlexgrid2

Dim RecordCount() As String
Dim bFound As Boolean
Dim i As Integer
Dim k As Integer
Dim rc As Integer
Dim strMsg As String

ReDim RecordCount(0 To 0)

'Get Distinct List of years
For k = 1 To MSHFlexGrid2.Rows - 1
   If MSHFlexGrid2.TextMatrix(k, 4) <> "" Then
      On Error Resume Next
         bFound = False
         For i = 0 To UBound(RecordCount())
            If Left(RecordCount(i), 4) = Left(MSHFlexGrid2.TextMatrix(k, 4), 4) Then
               bFound = True
            End If
         Next
         If bFound = False Then
            RecordCount(UBound(RecordCount())) = Left(MSHFlexGrid2.TextMatrix(k, 4), 4) & " = 0 Records"
            ReDim Preserve RecordCount(0 To UBound(RecordCount()) + 1)
         End If
      On Error GoTo 0
   End If
Next k

   
''set Count for each Distinct Year
For i = 0 To UBound(RecordCount()) - 1
   For k = 1 To MSHFlexGrid2.Rows - 1
      If Left(RecordCount(i), 4) = Left(MSHFlexGrid2.TextMatrix(k, 4), 4) Then
         rc = CInt(Replace(Right(RecordCount(i), Len(RecordCount(i)) - InStr(1, RecordCount(i), "= ") - 1), " Records", ""))
         RecordCount(i) = Left(RecordCount(i), 4) & " = " & CStr(rc + 1) & " Records"
      End If
   Next k
Next

For i = 0 To UBound(RecordCount())
   strMsg = strMsg & RecordCount(i) & vbCrLf
Next i

MsgBox strMsg

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