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How to assign the match of string to another variable in perl?
Posted on 2012-12-21
I try to assign the matched result to another variable but instead the other variable gets the value 1 which means that there is match.
Here is the example:
$infoArray[3] is something like this: Client root: some/path/in/here
Expected result for $clientRoot:
Here is the example:
my ($clientRoot) = $infoArray[3] =~ /Client root:\s.*/;
$infoArray[3] is something like this: Client root: some/path/in/here
Expected result for $clientRoot:
some/path/in/here
[X]
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6 Comments
I normally use my other pattern but why didn't it work in here? Is it because I have an array instead of a single variable?
Active 6 days ago
Or, more verbosely:
if ($infoArray[3] =~ m{Client root:\s+(.*)}) {
$clientRoot = $1;
}
my ($clientRoot) = ($infoArray[3] =~ m{Client root:\s+(.*)});
You can do it this way:
my ($clientRoot) = $infoArray[3] =~ /Client root:\s(.*)/;
Only difference is the capturing group in the regex.
my ($clientRoot) = $infoArray[3] =~ /Client root:\s(.*)/;
Only difference is the capturing group in the regex.
Active 6 days ago
Your original pattern did not work because you forgot the capturing parens (see my second option for the correct equivalent of your original idea (which I missed when reading the question)). The parens around the match may not be required in mine but I usually include them just to make precedence explicit.
my ($clientRoot) = ($infoArray[3] =~ m{Client root:\s+(.*)});
Active today
It did work, but the only thing output is the entire match. This is because you didn't specify any capture groups (parentheses, like brendonfeeley demonstrated). When you capture the result of a regex in list context in Perl, the capture groups are what are output to the variable. Since you didn't specify any groups, the output reverted to the overall match.
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