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Habi Z
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host ip address

I have a question and I can not figure the answer. I wonder if anyone can explain it to me.

The question is which of the following IP can be assigned to a host when using the subnet mask 255.255.240.0.

A. 113.10.4.0
B. 186.54.3.0
c.175.33.3.255
d.26.35.2.255
e.152.135.7.0
f.17.35.36.0

I really dont know how to tell what IP the host can be assigned. May be if any one can explain to me . I dont really care which options are correct as long as i have a way to find out. Please help.
Network ArchitectureNetwork AnalysisNetwork Operations

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Habi Z

8/22/2022 - Mon
ASKER CERTIFIED SOLUTION
Darr247

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Darren S

As we are dealing with a class B addressing scheme (128-191 in the first octet), wouldnt the answer be B, C & E?

I'm a few years since last looking at networking so forgive me if I'm wrong.
edster9999

All of these are valid IPs that you could give to a host.
You'll need to make the question more detailed
Akinsd

Daryl4 nailed it on the head, so I will just continue from where he stopped.

If it is a general question, then all the IPs can be assigned to a host.
If in a private address scheme, then none of them can be applied to a host as all of them are public addresses (RFC 1918).

I think the question just wants to test your understanding of broadcast address and network ID. These two are always present in a subnet and cannot be assigned to host.

If your subnet mask was 255.255.255.0 (/24 notation), then none of them can be assigned either as all the ones ending with 0 in the 4th (or last) octet would be Network IDs while the ones ending in 255 in the last (or 4th) octet would all be Broadcast addresses.

I recommend studying more on Network IDs and Broadcast Addr - That's what the question is about - I presume
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Habi Z

ASKER
Gentlemen,

Thank you for reply.  I will analyze it from here and get to see what is suitable answer. I have this on my question and I was never able to get around it.

Thanks