troubleshooting Question
building a query from one table with multiple betweens and or ors
binaryman101
asked on
asked on
Hello-
I have a very complex (well I think it is complex anyway) query I need written. I am running MSSQL 2005.
I am wishing to have a query tell me the tasks that need to be completed at a specific time. These tasks are all unique and there are about 75 different tasks that should show up at various times of the week and or year and or time of day.
For example: I have "clean baseboards" in the "tasksubject" field and "a more descriptive explanation" in the "taskbody" field. This task should only be done between the hours of 16:00 and 23:59 hours in the month of December only and only on a Friday.
I plan to run this query 3 times a day to produce a result. I just need the query in a view format and I can do the rest. The query will be ran @ 00:05 @ 8:05 and @ 16:05 every day.
The other data for the time field is 17:00
The data in the month fields s
Here is the table with the following columns (I have all data types set to nvarchar(MAX) I can easily change that if needed): I also put the common data that would be in each of the fields)
tasksubject (text and always different)
taskbody (text and always different)
dayofweek (Only a MON, TUE, WED, THU, FRI, SAT, SUN - but it could have more than one not just one)
month (Only a 1,2,3,4,5,6,7,8,9,10,11,12
time (always in military time and just XX:XX)
So with the example I have above it has the following data in each column:
tasksubject: clean baseboards
taskbody: a more descirptive explanation
dayofweek: FRI
month: 12
time: 17:00
Another example:
tasksubject: clean toaster
taskbody: clean out the toaster in the breakroom
dayofweek: MON, THU, SAT
month: 1,2,3,4,5,6,7,8,9,10,11,12
time: 11:00
This above example would create a result on Monday, Tuesday, and Saturday every month at 11 AM.
I will be running this query like I mentioned above 3 times a day so I think a between statement would be used for the date time.
If you have questions please let me know. I am sure this is a lot of work and I really appreciate it.
Ben
I have a very complex (well I think it is complex anyway) query I need written. I am running MSSQL 2005.
I am wishing to have a query tell me the tasks that need to be completed at a specific time. These tasks are all unique and there are about 75 different tasks that should show up at various times of the week and or year and or time of day.
For example: I have "clean baseboards" in the "tasksubject" field and "a more descriptive explanation" in the "taskbody" field. This task should only be done between the hours of 16:00 and 23:59 hours in the month of December only and only on a Friday.
I plan to run this query 3 times a day to produce a result. I just need the query in a view format and I can do the rest. The query will be ran @ 00:05 @ 8:05 and @ 16:05 every day.
The other data for the time field is 17:00
The data in the month fields s
Here is the table with the following columns (I have all data types set to nvarchar(MAX) I can easily change that if needed): I also put the common data that would be in each of the fields)
tasksubject (text and always different)
taskbody (text and always different)
dayofweek (Only a MON, TUE, WED, THU, FRI, SAT, SUN - but it could have more than one not just one)
month (Only a 1,2,3,4,5,6,7,8,9,10,11,12
time (always in military time and just XX:XX)
So with the example I have above it has the following data in each column:
tasksubject: clean baseboards
taskbody: a more descirptive explanation
dayofweek: FRI
month: 12
time: 17:00
Another example:
tasksubject: clean toaster
taskbody: clean out the toaster in the breakroom
dayofweek: MON, THU, SAT
month: 1,2,3,4,5,6,7,8,9,10,11,12
time: 11:00
This above example would create a result on Monday, Tuesday, and Saturday every month at 11 AM.
I will be running this query like I mentioned above 3 times a day so I think a between statement would be used for the date time.
If you have questions please let me know. I am sure this is a lot of work and I really appreciate it.
Ben
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