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MYSQL Join two same tables
Posted on 2012-12-27
Hello,
I have Two Tables that hold the number of transactions a shop did per hour by date. They hold the type1trans which is the ones done outside the shop and type 2 done inside:
CREATE TABLE IF NOT EXISTS `type1trans` (
`date` date NOT NULL,
`hour` int(10) NOT NULL,
`shopcode` int(10) NOT NULL,
`trans` int(10) NOT NULL,
KEY `date` (`date`,`sitecode`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
CREATE TABLE IF NOT EXISTS `type2trans` (
`date` date NOT NULL,
`hour` int(10) NOT NULL,
`shopcode` int(10) NOT NULL,
`trans` int(10) NOT NULL,
KEY `date` (`date`,`sitecode`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
I want to do a query, (with a where shopcode=123 for just per shop) that will sum(trans) by date (not worried about by hour) where I can end up with the sum of type1 trans by date and sum of type 2 and also the sum of type 1 and type 2 (to get total) by date.
eg
type1trans | type2trans | totaltrans | date
100 200 300 2012-12-27
Its important to note that on some days the type1trans are 0 so they don't have a record for that date in the type1trans table.
thank you if you can help.
I have Two Tables that hold the number of transactions a shop did per hour by date. They hold the type1trans which is the ones done outside the shop and type 2 done inside:
CREATE TABLE IF NOT EXISTS `type1trans` (
`date` date NOT NULL,
`hour` int(10) NOT NULL,
`shopcode` int(10) NOT NULL,
`trans` int(10) NOT NULL,
KEY `date` (`date`,`sitecode`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
CREATE TABLE IF NOT EXISTS `type2trans` (
`date` date NOT NULL,
`hour` int(10) NOT NULL,
`shopcode` int(10) NOT NULL,
`trans` int(10) NOT NULL,
KEY `date` (`date`,`sitecode`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
I want to do a query, (with a where shopcode=123 for just per shop) that will sum(trans) by date (not worried about by hour) where I can end up with the sum of type1 trans by date and sum of type 2 and also the sum of type 1 and type 2 (to get total) by date.
eg
type1trans | type2trans | totaltrans | date
100 200 300 2012-12-27
Its important to note that on some days the type1trans are 0 so they don't have a record for that date in the type1trans table.
thank you if you can help.
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12 Comments
I have done the query in MS SQL but you can easily modify it for MySQL
DECLARE @type1trans TABLE (
[DATE] DATE NOT NULL,
[HOUR] INT NOT NULL,
shopcode INT NOT NULL,
trans INT NOT NULL
)
INSERT INTO @type1trans VALUES ('2012-12-01', 4, 231, 17)
INSERT INTO @type1trans VALUES ('2012-12-01', 5, 321, 15)
INSERT INTO @type1trans VALUES ('2012-12-03', 3, 231, 12)
INSERT INTO @type1trans VALUES ('2012-12-04', 6, 231, 10)
DECLARE @type2trans TABLE (
[DATE] DATE NOT NULL,
[HOUR] INT NOT NULL,
shopcode INT NOT NULL,
trans INT NOT NULL
)
INSERT INTO @type2trans VALUES ('2012-12-01', 4, 321, 45)
INSERT INTO @type2trans VALUES ('2012-12-02', 4, 321, 45)
INSERT INTO @type2trans VALUES ('2012-12-01', 6, 231, 14)
INSERT INTO @type2trans VALUES ('2012-12-02', 6, 231, 10)
INSERT INTO @type2trans VALUES ('2012-12-03', 6, 231, 24)
INSERT INTO @type2trans VALUES ('2012-12-04', 6, 231, 42)
INSERT INTO @type2trans VALUES ('2012-12-05', 6, 231, 5)
INSERT INTO @type2trans VALUES ('2012-12-03', 8, 543, 40)
;WITH cteType2 AS (
SELECT
SUM(HOUR) AS 'Type2Hours'
,SUM(trans) AS 'Type2Trans'
,[DATE]
,shopcode
FROM
@type2trans
GROUP BY
shopcode
,[DATE]
)
,cteType1 AS (
SELECT
SUM(HOUR) AS 'Type1Hours'
,SUM(trans) AS 'Type1Trans'
,[DATE]
,shopcode
FROM
@type1trans
GROUP BY
shopcode
,[DATE]
)
SELECT
ISNULL(c1.Type1Trans, 0) AS 'Type1Trans'
,ISNULL(c2.Type2Trans, 0) AS 'Type2Trans'
,ISNULL(c1.Type1Trans, 0) + ISNULL(c2.Type2Trans, 0) AS 'TotalTrans'
,c2.[DATE]
,c2.shopcode
FROM
cteType2 c2
LEFT JOIN cteType1 c1 ON c2.shopcode = c1.shopcode AND c2.DATE = c1.DATE
WHERE
c2.shopcode = 231
Select X.type1transsum ,Y.type2transsum , (X.type1transsum +Y.type2transsum) , X.date
From (
Select sum(trans) as type1transsum
,date from type1trans
group by date
)X
Left join (
Select sum(trans) as type2transsum
,date from type2trans
group by date ) on X.date = Y.date)
From (
Select sum(trans) as type1transsum
,date from type1trans
group by date
)X
Left join (
Select sum(trans) as type2transsum
,date from type2trans
group by date ) on X.date = Y.date)
try this
Select X.type1transsum ,Y.type2transsum , (X.type1transsum +Y.type2transsum) , X.date
From (
Select sum(trans) as type1transsum
,date from type1trans
group by date
)X
Left join (
Select sum(trans) as type2transsum
,date from type2trans
group by date ) Y on X.date = Y.date)
Select X.type1transsum ,Y.type2transsum , (X.type1transsum +Y.type2transsum) , X.date
From (
Select sum(trans) as type1transsum
,date from type1trans
group by date
)X
Left join (
Select sum(trans) as type2transsum
,date from type2trans
group by date ) Y on X.date = Y.date)
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')' at line 10
SELECT
ISNULL(t1.Type1Trans, 0) AS 'Type1Trans'
,ISNULL(t2.Type2Trans, 0) AS 'Type2Trans'
,ISNULL(t1.Type1Trans, 0) + ISNULL(t2.Type2Trans, 0) AS 'TotalTrans'
,t2.[DATE]
,t2.shopcode
FROM
(
SELECT
SUM(HOUR) AS 'Type2Hours'
,SUM(trans) AS 'Type2Trans'
,[DATE]
,shopcode
FROM
type2trans
GROUP BY
shopcode
,[DATE]
)T2
LEFT JOIN
(
SELECT
SUM(HOUR) AS 'Type1Hours'
,SUM(trans) AS 'Type1Trans'
,[DATE]
,shopcode
FROM
type1trans
GROUP BY
shopcode
,[DATE]
)T1 ON t2.shopcode = t1.shopcode AND t2.DATE = t1.DATE
WHERE
t2.shopcode = 231
ISNULL(t1.Type1Trans, 0) AS 'Type1Trans'
,ISNULL(t2.Type2Trans, 0) AS 'Type2Trans'
,ISNULL(t1.Type1Trans, 0) + ISNULL(t2.Type2Trans, 0) AS 'TotalTrans'
,t2.[DATE]
,t2.shopcode
FROM
(
SELECT
SUM(HOUR) AS 'Type2Hours'
,SUM(trans) AS 'Type2Trans'
,[DATE]
,shopcode
FROM
type2trans
GROUP BY
shopcode
,[DATE]
)T2
LEFT JOIN
(
SELECT
SUM(HOUR) AS 'Type1Hours'
,SUM(trans) AS 'Type1Trans'
,[DATE]
,shopcode
FROM
type1trans
GROUP BY
shopcode
,[DATE]
)T1 ON t2.shopcode = t1.shopcode AND t2.DATE = t1.DATE
WHERE
t2.shopcode = 231
Thanks RehanYousaf but that does not work it gives this error #1241 - Operand should contain 1 column(s)
Select X.type1transsum ,Y.type2transsum , (X.type1transsum +Y.type2transsum) , X.date
From (
Select sum(trans) as type1transsum
,date from type1trans
group by date
)X
Left join (
Select sum(trans) as type2transsum
,date from type2trans
group by date ) Y on X.date = Y.date
above looks to have worked (checking result) - I rmeoved the ) at the end.
From (
Select sum(trans) as type1transsum
,date from type1trans
group by date
)X
Left join (
Select sum(trans) as type2transsum
,date from type2trans
group by date ) Y on X.date = Y.date
above looks to have worked (checking result) - I rmeoved the ) at the end.
this works to show what I want but:
Select X.type1transsum ,Y.type2transsum , (X.type1transsum +Y.type2transsum) , X.`date`
From (
Select sum(trans) as type1transsum
,`date` from type1trans where shopcode=1037
group by `date`
)X
Left join (
Select sum(trans) as type2transsum
,`date` from type2trans where shopcode=1037
group by `date` ) Y on X.`date` = Y.`date`
For the dates where there is no records in the type1trans then there is no record shown for the type2 dates and a total for that date being the same as type2 since type1 null. How can I get type1 to return null for the date?
Select X.type1transsum ,Y.type2transsum , (X.type1transsum +Y.type2transsum) , X.`date`
From (
Select sum(trans) as type1transsum
,`date` from type1trans where shopcode=1037
group by `date`
)X
Left join (
Select sum(trans) as type2transsum
,`date` from type2trans where shopcode=1037
group by `date` ) Y on X.`date` = Y.`date`
For the dates where there is no records in the type1trans then there is no record shown for the type2 dates and a total for that date being the same as type2 since type1 null. How can I get type1 to return null for the date?
Select IFNULL(X.type1transsum ,0) as type1sum,IFNULL(Y.type2tra
From (
Select sum(trans) as type1transsum
,`date` from type2trans where shopcode=1037
group by `date`
)X
Left join (
Select sum(trans) as type2transsum
,`date`, shopcode from type1trans where shopcode=1037
group by `date` ) Y on X.`date` = Y.`date`
From (
Select sum(trans) as type1transsum
,`date` from type2trans where shopcode=1037
group by `date`
)X
Left join (
Select sum(trans) as type2transsum
,`date`, shopcode from type1trans where shopcode=1037
group by `date` ) Y on X.`date` = Y.`date`
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