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Difference between two arrays, PHP?
Posted on 2012-12-27
Hi, I have two arrays:
array1=(200,201,202,203)
array2=(200,201)
What do I do to get the difference of the array to be (202,203). When I run the array_diff function I get the result as (200,201) and this is not my desired result. Thanks for the help.
A
array1=(200,201,202,203)
array2=(200,201)
What do I do to get the difference of the array to be (202,203). When I run the array_diff function I get the result as (200,201) and this is not my desired result. Thanks for the help.
A
[X]
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<?php
$array1 = array("a" => "green", "red", "blue", "red");
$array2 = array("b" => "green", "yellow", "red");
$result = array_diff($array1, $array2);
print_r($result);
?>
result
Array
(
[1] => blue
)
source
http://php.net/manual/en/function.array-diff.php
array_idff will give diff only
<?php
$array1 = array("a" => "green", "red", "blue", "red");
$array2 = array("b" => "green", "yellow", "red");
$result = array_diff($array1, $array2);
print_r($result);
?>
refer
http://php.net/manual/en/function.array-diff.php
share your code to see in detail
<?php
$array1 = array("a" => "green", "red", "blue", "red");
$array2 = array("b" => "green", "yellow", "red");
$result = array_diff($array1, $array2);
print_r($result);
?>
refer
http://php.net/manual/en/function.array-diff.php
share your code to see in detail
To anybody wanting a double-sided array_diff - mentioned by rudigier at noxx dot at. Remember, array_diff gives you everything in the first array that isn't in the subsequent arrays.
$array1=array('blue','red'
$array2=array('blue','yell
array_merge(array_diff($ar
Result
------
Array
(
[0] => red
[1] => yellow
)
$array1=array('blue','red'
$array2=array('blue','yell
array_merge(array_diff($ar
Result
------
Array
(
[0] => red
[1] => yellow
)
Active today
Works fine from here so you'll have to show some code to see what you're doing differently.
Thank you for getting back to me. As I had mentioned in my question I tried array_diff and it does not work. I have attached my code for your reference. Is there any other way this can be done?
$extens= $_GET['extsn']; //comma seperated values; 200,201
$extss = explode(",",$extens); //puts it into an array
echo "The nums to delete :".$extens;
/**********get existing extens from the DB*********/
$stmt = $db->query("SELECT val from queues where name='extension' and id='$group_number'");
$row = $stmt->fetch(PDO::FETCH_ASSOC);
$existing_exts= implode(",",$row); //200,201,202,203
echo "Existing nos ".$existing_exts;
/*****End************/
$exten_array =array_diff($extss,$row);
$exten_nos=implode(",",$exten_array);
echo "difference is :". $exten_nos; //output is 200,201
As per PHP manual, array_diff Returns an array containing all the entries from array1 that are not present in any of the other arrays.
But you can also build your own simple function like this:
But you can also build your own simple function like this:
function arrDiff($arr1, $arr2){
foreach($arr1 as $key=>$value){
if (!array_search($value, $arr2)){
$result[]=$value;
}
}
if (count($result)>0){ // it will only return 0 if $result is NULL, if it's a string it will be 1!!!!
return $result;
} else {
return false;
}
}
Questions like this scream out for SSCCE.
<?php // RAY_temp_aej1973.php
error_reporting(E_ALL);
echo '<pre>';
// http://php.net/manual/en/function.array-diff.php
$array1 = array(200,201,202,203);
$array2 = array(200,201);
var_dump( array_diff($array1, $array2) );
var_dump( array_diff($array2, $array1) );
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