# using RECURSIVE WITH statement - using oracle 11g

Hello
Is it possible to use sql statement (not PLSQL) to solve the following - eg
Table1 has 2 columns - dates and an amount against each date.
Assume 4 years of data ....
Date                  Amount
01/01/2000          25
01/02/2000          46
etc etc
Here is the logic - lets say for the first year from 01/01/2000 through to 31/12/2000 has a max value in that date range of 46.
I then want to jump forward by one month and work out the next max value - date range
01/02/2000 through to 01/01/2001 and the max value in that range is say 56.
I want to carry out this process for all the dates in the table and in theory will have a number of max values for reach time window where I jump foward by one month.
I then want the max of all the max values.
eg max(46,56,......................................)
Hope this makes sense

Regards
Peter Kwan

What's the point of using recursive function for your target output? You can just get the max of all the amount.
select trunc(date,'MM') date, max(amount) amount
from table1
group by cube(trunc(date,'MM') )  -- group by month, the cube gives extra totals for each level
-- in the group
order by trunc(date,'MM')

Are there  time-windows without data ?  If yes, what should happen with them ?
>I then want the max of all the max values.
isn't that the overall max() value?
i mean, what is the point of getting the "intermediate" maxes, if the end result is 1 single max value?

Sorry - I meant the average for each time window - so, assume the average is 22 then 45
I then want
max(22,45,......................................)
Regards

flow001
No time windows without date
so you want the MAX() over the monthly averages?

select max( avg_value )
from ( select average(value), trunc(date, 'MM') from yourtable group by trunc(date, 'MM') )

See attached as this should make it clear - the answer is in cell C111
recursive.xls
Please see if the following works (not tested):

``````select max(avg_amt) from
(
select average(amount) avg_amt over (order by date range between current row and 11 following)
from table1
)``````
Guy Hengel [angelIII / a3]

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angelIII