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How to echo captured values whithin a Read-Host statement ?
Posted on 2012-12-28
Hello all,
I am working in a little project that involves reading a csv file, query ad against the csv file and set the the right values in AD.
Through the code I have captured the following values
$AD_USER.sn
$InputLastName
$InputLastName = Read-Host 'Type the new Last Name:'
$NewLastName = Read-Host 'Are you sure, you want to replace the following lastname "$($AD_USER.sn)" by $($InputLastName) (Y/N)'
So, when I ask the question: 'Are you sure, you want to replace the following lastname "$($AD_USER.sn)" by $($InputLastName) (Y/N)',
So, not sure how to echo the values previously captured on $AD_USER.sn and $InputLastName in the Read-Host statement
Thanks for your help,
I am working in a little project that involves reading a csv file, query ad against the csv file and set the the right values in AD.
Through the code I have captured the following values
$AD_USER.sn
$InputLastName
$InputLastName = Read-Host 'Type the new Last Name:'
$NewLastName = Read-Host 'Are you sure, you want to replace the following lastname "$($AD_USER.sn)" by $($InputLastName) (Y/N)'
So, when I ask the question: 'Are you sure, you want to replace the following lastname "$($AD_USER.sn)" by $($InputLastName) (Y/N)',
So, not sure how to echo the values previously captured on $AD_USER.sn and $InputLastName in the Read-Host statement
Thanks for your help,
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8 Comments
Are you sure you dont want to make do it this way ?
$InputNewLastName = Read-Host 'Type the new Last Name:'
$NewLastName = Read-Host 'Are you sure, you want to replace the following lastname "$($AD_USER.sn)" by $($InputNewLastName) (Y/N)'
$InputNewLastName = Read-Host 'Type the new Last Name:'
$NewLastName = Read-Host 'Are you sure, you want to replace the following lastname "$($AD_USER.sn)" by $($InputNewLastName) (Y/N)'
Active today
Try
$InputNewLastName = Read-Host "Type the new Last Name"
$NewLastName = Read-Host "Are you sure, you want to replace the following lastname $($AD_USER.sn) by $($InputNewLastName) (Y/N)"
Nope. I get the following:
Are you sure, you want to replace the following lastname $($AD_USER.sn) by $($InputLastName) (Y/N)
Thanks, G
Are you sure, you want to replace the following lastname $($AD_USER.sn) by $($InputLastName) (Y/N)
Thanks, G
Active today
'Single Quote' does not expand the variable but "Double quotes" should..
This is what I get..
This is what I get..
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