Return Single Day of Week/Date for an annual query
Checks may have been written on several dates during the week.
I only want to return the date for Thursday each week.
This did not work but should illustrate what I’m trying to do.
set DateFirst 5 -- Friday
select
datepart( ww, p.[CHECKDATE]) [Week]
, sum(p.[INSURANCE]) [Insurance]
, (select convert( varchar(10), p.[CHECKDATE], 1) where datepart( ww, p.[CHECKDATE]) = 4 ) [CheckDate]
from [PAYROLL] p
where p.[CHECKDATE] >= '01/01/2012'
and p.[CHECKDATE] < '01/01/2013'
and p.[ INSURANCE] <> 0.00
group by datepart( ww, p.[CHECKDATE]), p.[CHECKDATE]
set DateFirst 7 -- Always be sure to set it back
http://stackoverflow.com/questions/3839923/get-date-of-all-saturdays-in-a-given-year-sql-server
The following query would return you all the Thursdays in 2012:
declare @d datetime
declare @d = '20120101'
select dateadd(dd,number,@d)
from master..spt_values
where type = 'P'
and year (dateadd(dd,number,@d) = year(@d)
and datepart(dw,dateadd(dd,number,@d)) = 5
So maybe you could have your base query for your checks and add a final part to it of something like
and CHECKDATE in (the select above)
You'd need to do a little date manipulation to truncate the dates to midnight of the dates returned only or convert to char with just the dates (which is horrible on indexing), but hopefully that gives you a good starting point.
set DateFirst 5 -- Friday
select
DATEPART(ww, p.[CHECKDATE]) [Week]
, SUM(p.[INSURANCE]) [Insurance]
, p.[CHECKDATE] [CheckDate]
from [PAYROLL] p
where p.[CHECKDATE] >= '01/01/2012'
and p.[CHECKDATE] < '01/01/2013'
and p.[ INSURANCE] <> 0.00
and DATEPART(ww, p.[CHECKDATE]) = 4
group by p.[CHECKDATE]
set DateFirst 7 -- Always be sure to set it back
The performance will suffer because of the function on the p.[CHECKDATE] column, but the above should do what you desire. You could try with the table of dates LEFT OUTER JOIN [PAYROLL] ON p.[CHECKDATE] = [Thursday Date] to see if it performs better as it probably will even though you have to introduce more code.
select dateadd(dd, number, '2012') as StartDT
, dateadd(dd, number+1, '2012') as EndDT
from master..spt_values
where type = 'P'
and dateadd(dd, number, '2012') < '2013'
and datename(dw, dateadd(dd, number, '2012')) = 'Thursday'
Then in the JOIN, I would use:
ON p.[CHECKDATE] >= d.StartDT and p.[CHECKDATE] < d.EndDT
You could then group on d.StartDT to ensure you got every record for that day regardless of timestamp.
If a check is written on Friday, does it count in the NEXT Thu's total or the PREVIOUS Thu's?
For example, should a check written on Fri, Dec 21 be included in Dec 20's total or Dec 27's?
If a check is written on Saturday, does it count in the NEXT Thu's total or the PREVIOUS Thu's?
For example, should a check written on Sat, Dec 22 be included in Dec 20's total or Dec 27's?
Our payroll period ends / journals on Thursday at midnight.
These other suggestions would drop the insurance amounts on checks not printed on Thursday.
I’m looking to accumulate all checks insurance for the journal week, only returning the journal date.
Typically things like this I would create a temp table with the weeks then, accumulate the totals on a second pass.
Just looking for a silver bullet. Nice to hear from you, thanx:) Greg
PS this is Obama care making work for us, at least it pays well:)
select dateadd(dd, number-7, '2012') as StartDT
, dateadd(dd, number, '2012') as EndDT
from master..spt_values
where type = 'P'
and dateadd(dd, number, '2012') < '2013'
and datename(dw, dateadd(dd, number, '2012')) = 'Friday'
This gives you the date for Friday at midnight as well as the previous week's Friday at midnight. You JOIN to your data as:
ON p.[CHECKDATE] >= d.StartDT and p.[CHECKDATE] < d.EndDT
This will give you all the insurance checks written after last Friday at midnight up to (but not including) this Friday at midnight.
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