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Formatting the output using For XML Path

Posted on 2013-01-07
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Last Modified: 2013-01-08
Hi:

I've created the query below:
SELECT o.OrderID AS "Order/OrderID",
   o.OrderNumber AS "Order/OrderNumber",
   o.BillToFirstName AS "Order/BillToFirstName",
   o.BillToLastName AS "Order/BillToLastName",
   (Select p.Amount from ac_Payments p where p.OrderID = o.OrderID FOR XML PATH ('')) AS "Order/Payments/Amount"
FROM ac_Orders AS o
   INNER JOIN ac_OrderItems as oi
   ON o.OrderID = oi.OrderID
WHERE o.OrderID=104
FOR XML PATH ('O'), ROOT ('Orders'), ELEMENTS;

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Works well, except for one issue.  The output of the result (below) seems to include the Amount tag twice, and the second instance shows the HTML code instead of the actual greater than, and less than signs.

How do I get rid of the second instance of the <amount> tag?

<Orders>
	<O>
		<Order>
			<OrderID>104</OrderID>
			<OrderNumber>104</OrderNumber>
			<BillToFirstName>Jean</BillToFirstName>
			<BillToLastName>Denny</BillToLastName>
				<Payments>
				<Amount>&lt;Amount&gt;39.4400&lt;/Amount&gt;</Amount>
				</Payments>
		</Order>
	</O>
<Orders>

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0
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Question by:W2Market
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2 Comments
 
LVL 23

Accepted Solution

by:
Steve Wales earned 2000 total points
ID: 38752917
I don't claim to be an expert in XML and of course, I don't have your database to test this with but it would seem that this might work:

SELECT o.OrderID AS "Order/OrderID",
   o.OrderNumber AS "Order/OrderNumber",
   o.BillToFirstName AS "Order/BillToFirstName",
   o.BillToLastName AS "Order/BillToLastName",
   (Select p.Amount from ac_Payments p where p.OrderID = o.OrderID) AS "Order/Payments/Amount"
FROM ac_Orders AS o
   INNER JOIN ac_OrderItems as oi
   ON o.OrderID = oi.OrderID
WHERE o.OrderID=104
FOR XML PATH ('O'), ROOT ('Orders'), ELEMENTS;

Open in new window

                                 

You were already turning the Amount from ac_Payments into XML and then applying XML on top of already XML output.

Try that and let us know.
0
 

Author Closing Comment

by:W2Market
ID: 38755238
Perfect.  Thanks for your help!
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