hierarchical records into rows

Posted on 2013-01-08
Last Modified: 2013-01-08

I have a table with a hierarchy of pharmacy info. It is received on a completely different format than we need.
It is not a fixed amount of levels in the hierarchy. It can be up to 8, but some may only have 2.
The "Drug_Parent" in the drug level one step higher. THe "Ulimate_Parent" is the highest level in that particular hierarchy.
Basically, if the drug has an "Ulitmate Parent" = 0, then that is the top level in the hierarchy.

We've got something to get us started, but we figure that there has to be a better way. Especially if they keep expanding the amount of tiers in the hierarchy.

---raw format
001       PAINKILLER      0            0            1
002           ASPRIN            001            001            2
003      CHILD ASPRIN      002            001            3
007          Anti-Fungal      0            0            1
009         Fungal-Cream      007            007            2      

---Desired Output

001        PAINKILLER  002       ASPRIN                                 003       CHILD ASPRIN
007            anit-Fungal    009       Fungal-Cream                 NULL     NULL
Question by:jvoconnell
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LVL 74

Accepted Solution

sdstuber earned 500 total points
ID: 38755328
SELECT REGEXP_SUBSTR(ids, '[^/]+', 1, 1) drug_id1,
       REGEXP_SUBSTR(names, '[^/]+', 1, 1) drug_name1,
       REGEXP_SUBSTR(ids, '[^/]+', 1, 2) drug_id2,
       REGEXP_SUBSTR(names, '[^/]+', 1, 2) drug_name2,
       REGEXP_SUBSTR(ids, '[^/]+', 1, 3) drug_id3,
       REGEXP_SUBSTR(names, '[^/]+', 1, 3) drug_name3,
       REGEXP_SUBSTR(ids, '[^/]+', 1, 4) drug_id4,
       REGEXP_SUBSTR(names, '[^/]+', 1, 4) drug_name4,
       REGEXP_SUBSTR(ids, '[^/]+', 1, 5) drug_id5,
       REGEXP_SUBSTR(names, '[^/]+', 1, 5) drug_name5,
       REGEXP_SUBSTR(ids, '[^/]+', 1, 6) drug_id6,
       REGEXP_SUBSTR(names, '[^/]+', 1, 6) drug_name6,
       REGEXP_SUBSTR(ids, '[^/]+', 1, 7) drug_id7,
       REGEXP_SUBSTR(names, '[^/]+', 1, 7) drug_name7,
       REGEXP_SUBSTR(ids, '[^/]+', 1, 8) drug_id8,
       REGEXP_SUBSTR(names, '[^/]+', 1, 8) drug_name8
  FROM (SELECT     SYS_CONNECT_BY_PATH(drug_id, '/') ids,
                   SYS_CONNECT_BY_PATH(drug_name, '/') names,
                   CONNECT_BY_ISLEAF isleaf
              FROM yourtable
        CONNECT BY drug_parent = PRIOR drug_id
        START WITH drug_parent = 0)
 WHERE isleaf = 1

Author Closing Comment

ID: 38755519
AMAZING! I've never been exposed to that before. We were handling this in 100 lines of code that was extremely confusing to read and took longer to run. This works great. I just had to change the '/' to another value due to an ora-30004 error. Thank you so much.
LVL 74

Expert Comment

ID: 38755633
glad I could help

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