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how to declare a 2-dimensional version of strlen

Posted on 2013-01-09
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Last Modified: 2015-05-28
I need to know how to write a declaration, including arguments and result, for a 2-dimensional version of strlen (that is, a function that receives an array of points to char and an array size of size_t integers, and an int that specifies the number of elements in each array.
Not sure if this is correct but I have:  

2dimstrlen(char **pointers, size_t *integers, int number)

can you verify if this is correct?
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Question by:rnformatix
4 Comments
 
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Zoppo earned 500 total points
ID: 38761941
Hi rnformatix,

you just want to know if the function signature is correct? If so I'd say mostly: You pass an array of strings as pointer to char pointers, you pass an array to size_t as pointer and you pass the number of elements as int.

One wrong thing is the function name. Function names must not start with a number, so you should rename it to something like strlen2dim or something.

Another thing is you need to declare a return type, i.e. void. So it should look somehow like this:

void strlen2dim( char **pointers, size_t *integers, int number );

Hope that helps,

ZOPPO
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Expert Comment

by:Hugh McCurdy
ID: 38768600
Based on the information provided, it appears that Zoppo's advice is good.

I think, however that you should have a non-void return type.  The return type could indicate if there was an error or not.  One error is that you passed null for one of the pointers.  (Although another option is to make sure the program crashes but you might want the crash to be more graceful then the default.)
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