asked on

PHP Objects

Greetings, I have a variable that is instantiated as a PHP Object

$stats

$stats has some key->values assigned to it

$stats->gender = "male";
$stats->age = 34;

if I want the gender I can:
<?PHP echo $stats->gender ?>

what if I want the fieldname, not fieldvalue...
ie. I want "gender" to appear, not "male"...

Thanks.

sivagnanam chandrakanth

Use this

echo $key = key((array)$stats);

Evan Cutler

ASKER

Thank you sivagnanum_c,

How do I differentiate one from another?
There's gender and age...
How do I pick one out?

Thanks

Vimal DM

Hi,

just use the below code to print the field name

<?PHP
echo key($stats);
?>

Evan Cutler

ASKER

Ok, the problem is in this scenario, I have two fields....
How do I tell one from the other with that snippet?

Thanks.

SOLUTION

Vimal DM

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sivagnanam chandrakanth

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Member_2_248744

greetings arcee123 , , what you have said so far does not give me enough information about what you are trying to do AND what the Variables you have to start with ?

If you know the property Name (sometimes referred to as the KEY) you just echo out that
echo "This is the Age ".$stats->age;

However you can NOT have a variable like $var without the -> ($var->property) and get any info about a single Property name, because there is NO property specified with $var

you say "I have two fields.... How do I tell one from the other with that snippet"
can you show us the PHP code (variables) for the two fields ? It may make a difference in how to solve this.

Evan Cutler

ASKER

Thanks guys...most appreciated.