asked on

Show datediff result in year and days

Hi Experts

I am using below mentioned SQL query. The result of column DaysWithCompany=2859.
I need to display it into year and days like 7 year(s) 50 days or 0 year(s) 69 days (for new employee. Is there any function which can help me to get this result.

Select CC, EmpCode, EmpName, Name=Title+' '+EmpName, Designation, Department,
DaysWithCompany=Case When RegsinedOn is not null then DateDiff(day, JoiningDate, RegsinedOn)
else DateDiff(Day, JoiningDate, coalesce(RegsinedOn, getdate())) end
from Emp_Info a
Left Outer Join Emp_SalaryInfo b on a.TransNo=b.TransNoEmpInfo
where a.CC='01' and a.Empcode='00064'

Saurabh Bhadauria

exact representation in years and days will be tough...but you can get a approx representation...
like this...

Declare @Days int 
set @Days =2859 

select cast(@Days/365 as varchar(10))  + ' years and ' + cast(@Days%365 as varchar(10))  + ' Days'

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but it may fail for certain dates or for leap years...

Steve Wales

Did some searching around this morning and found this:

http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=170186

I've done some testing on it and this query seems to work. The base logic he gives is this:

DECLARE @d1 DATETIME, @d2 DATETIME;

SET @d1 = '20070228';
SET @d2 = '20080301';

DECLARE @years INT, @months INT, @days INT;

SET @years = (CAST(CONVERT(CHAR(8),@d2,112) AS INT)
   -CAST(CONVERT(CHAR(8),@d1,112) AS INT))/10000;
SET @months = (DATEDIFF(MONTH,@d1,@d2)+12)%12 - CASE WHEN DAY(@d1)>DAY(@d2) THEN 1 ELSE 0 end;
SET @days = DATEDIFF(day,DATEADD(month,@months,DATEADD(YEAR,@years,@d1)),@d2);

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There's an example in the post on doing it all with a CTE. I don't have your data to work with and I am not a huge CTE expert but following his example something like this might be close.

Since you allow nulls in your table for dates, you'll probably have to do some other trapping in there for nulls in RegsinedOn (maybe replace references to RegsinedOn with your coalesce(RegsinedOn, getdate).

with CTE as
(
Select CC, 
       EmpCode, 
       EmpName, 
       Name=Title+' '+EmpName, 
       Designation, 
       Department,
       DaysWithCompany=Case When RegsinedOn is not null then DateDiff(day, JoiningDate, RegsinedOn)
                            else DateDiff(Day, JoiningDate, coalesce(RegsinedOn, getdate())) 
                       end,
       (CAST(CONVERT(CHAR(8),RegsinedOn,112) AS INT)
        -
        CAST(CONVERT(CHAR(8),JoiningDate,112) AS INT)
       )/10000 AS [Years],
       (DATEDIFF(MONTH,JoiningDate,RegsinedOn)+12)%12 
        - 
        CASE WHEN DAY(JoiningDate)>DAY(RegsinedOn) THEN 1 ELSE 0 END  AS [Months]       
from Emp_Info a
Left Outer Join Emp_SalaryInfo b on a.TransNo=b.TransNoEmpInfo
where a.CC='01' and a.Empcode='00064' 
)
SELECT	*,
	DATEDIFF(day,DATEADD(month,[Months],DATEADD(YEAR,[Years],JoiningDate)),ResignedOn) AS [Days]
FROM	cte;

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See if that gets you started?

Mehram

ASKER

I did something like this. Is it ok?

SELECT      Convert(Varchar(10), DATEDIFF(d, JoiningDate, coalesce(RegsinedOn,getdate()))/365) + ' Years ' +
            Convert(Varchar(10), (DATEDIFF(d, JoiningDate, coalesce(RegsinedOn,getdate()))%365)/30) + ' Months ' +
            Convert(Varchar(10), (DATEDIFF(d, JoiningDate, coalesce(RegsinedOn,getdate()))%365)%30) + ' Days '
FROM Emp_Info

Steve Wales

What you're doing is only going to give you an estimate - if you're OK with that, then I guess it's OK.

Some years have 366 days instead of 365.
Some months have 28, 29 or 31 days instead of 30.

Your results will be a close estimate (the further apart the date difference, the more inaccurate it will be).

The query I posted (not my query, borrowed from the forum I linked) seems to produce accurate results across leap years and varying month lengths.

ASKER CERTIFIED SOLUTION

Scott Pletcher

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