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mysql: how to formulate WHERE for  2-out-of-3   "matches"

Posted on 2013-01-14
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Last Modified: 2013-01-14
i need to select records where at least 2 of 3 conditions are met.
How is this best done?
Below is probe code for what i'm after...

SELECT * FROM tbl WHERE
    A = 1
    OR
    B = 2
    OR
    C = 3

if the WHERE clause were an "expression language" then something like the following might suffice  which "adds up"  the successful terms in the "equation"

WHERE  (
   (if (A=1) then 1 else 0)
+
   (if (B=2) then 1 else 0)
+
   (if (C=3) then 1 else 0)

   )>=2


thanks!
0
Comment
Question by:willsherwood
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7 Comments
 
LVL 41

Assisted Solution

by:ralmada
ralmada earned 1332 total points
ID: 38775405
you could try

where       (case when A=1 then 1 else 0 end) +
      (case when B=2 then 1 else 0 end) +
      (case when C=3 then 1 else 0 end)  >= 2
0
 
LVL 48

Assisted Solution

by:Dale Fye
Dale Fye earned 668 total points
ID: 38775411
Not sure of the MySQL syntax, but try something like:

SELECT *,  (if(A=1, 1, 0) + if(B=2, 1, 0) + if(C=3, 1, 0)) as Matches
FROM yourTabletbl
WHERE (if(A=1, 1, 0) + if(B=2, 1, 0) + if(C=3, 1, 0)) >= 2
0
 
LVL 41

Accepted Solution

by:
ralmada earned 1332 total points
ID: 38775416
mysql also supports if()

so

where       if(A=1, 1, 0) +
      if(B=2, 1, 0) +
      if(C=3, 1, 0)  >= 2
0
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Author Closing Comment

by:willsherwood
ID: 38775423
excellent, many thanks.
this is easier than i had feared.
appreciated
0
 
LVL 48

Expert Comment

by:Dale Fye
ID: 38775511
The advantage of including the Matches column in the query results is that you can then identify how many of the matches were made.

Another alternative, if you want to be able to identify which conditions matched by simply looking at the Matches field would be:

SELECT *,  (if(A=1, "A","") & if(B=2, "B", "") & if(C=3, "C", "")) as Matches
FROM yourTabletbl
WHERE LEN(if(A=1, "A","") & if(B=2, "B", "") & if(C=3, "C", "")) >= 2
0
 

Author Comment

by:willsherwood
ID: 38775581
clever,  THANK YOU!
0
 
LVL 48

Expert Comment

by:Dale Fye
ID: 38775679
glad to help
0

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