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tsql select count last 10 minutes from tale getdate

Posted on 2013-01-15
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Last Modified: 2013-01-28
i have a table contain records and column datetimein

i want to select the last 10 min from getdate()

for example let say  the current date is  2013-01-15 1:09 PM
i want to get the number of records in each time s

 2013-01-15 1:09 PM numberofsms
 2013-01-15 1:08 PM
 2013-01-15 1:07 PM
 2013-01-15 1:06 PM
 2013-01-15 1:05 PM
 2013-01-15 1:04 PM
 2013-01-15 1:03 PM
 2013-01-15 1:02 PM
 2013-01-15 1:01 PM
 2013-01-15 1:00 PM
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Question by:afifosh
9 Comments
 
LVL 39

Expert Comment

by:appari
ID: 38777636
;with mins as (Select 1 duration
union all select duration+1 from mins where duration<10)
select dateadd(mi, duration, getdate()) from mins
0
 
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Expert Comment

by:mbizup
ID: 38777642
Try this:

SELECT *
FROM YourTable
WHERE datediff("n",YourField, getdate() ) < 10

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LVL 39

Expert Comment

by:Pratima Pharande
ID: 38777650
try this

SELECT count(*),convert(varchar(16),[CREATED_TIMESTAMP],121)
FROM tablename
WHERE [CREATED_TIMESTAMP] >= dateadd(minute,-10,getdate()) and
 [CREATED_TIMESTAMP] <= getdate()
AND Created_By ='FaxActivityMonitor'
Group by convert(varchar(16),[CREATED_TIMESTAMP],121)
Order by convert(varchar(16),[CREATED_TIMESTAMP],121) Desc
0
 
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Author Comment

by:afifosh
ID: 38777668
pratima_mcs this is your result


(No column name)      (No column name)
1      2013-01-15 13:21
2      2013-01-15 13:18
2      2013-01-15 13:16
1      2013-01-15 13:12


my table format

datetimein      msisdn      reqport      message
2011-01-09 07:52:54.907      506193110      84448      Mails1 has failed!
2011-01-09 07:57:56.423      506193110      84448      Mails1 has failed!
2011-01-09 08:02:57.547      506193110      84448      Mails1 has failed!

the old solution not compatible with my table
0
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LVL 39

Expert Comment

by:Pratima Pharande
ID: 38777694
what exact result you need , my solution provides count(*) for the in last 10 min , for each min

what change you required in this ?
0
 
LVL 1

Author Comment

by:afifosh
ID: 38777731
SUM(CASE WHEN DATEPART(hh, c.datetimein) = 0 THEN 1 ELSE 0 END) AS  'Midnight',
SUM(CASE WHEN DATEPART(hh, c.datetimein) = 1 THEN 1 ELSE 0 END) AS  '1:00 AM',
SUM(CASE WHEN DATEPART(hh, c.datetimein) = 2 THEN 1 ELSE 0 END) AS  '2:00 AM',
SUM(CASE WHEN DATEPART(hh, c.datetimein) = 3 THEN 1 ELSE 0 END) AS  '3:00 AM',
SUM(CASE WHEN DATEPART(hh, c.datetimein) = 4 THEN 1 ELSE 0 END) AS  '4:00 AM',
SUM(CASE WHEN DATEPART(hh, c.datetimein) = 5 THEN 1 ELSE 0 END) AS  '5:00 AM',
SUM(CASE WHEN DATEPART(hh, c.datetimein) = 6 THEN 1 ELSE 0 END) AS  '6:00 AM',
SUM(CASE WHEN DATEPART(hh, c.datetimein) = 7 THEN 1 ELSE 0 END) AS  '7:00 AM',
SUM(CASE WHEN DATEPART(hh, c.datetimein) = 8 THEN 1 ELSE 0 END) AS  '8:00 AM',

this one count record in each hours i want to count in each 5 minutes in each hours

i should care maybe i didn't recive any record in 1:44 min so i should get this record and with value 0

for example

getdate (hh) divide hours in minutes slot  and count the number of record group by date days hh mm  

and i can change the interval of minute slot 5 or 10 or 1 min..

and i want to select referring to the getdate()
0
 
LVL 1

Author Comment

by:afifosh
ID: 38777985
select dateadd(minute, 5 + (datediff(minute, 0, datetimein) / 5) * 5, 0),
       COUNT(*)
  FROM [radiomix].[dbo].[chat]
group by dateadd(minute, 5 + (datediff(minute, 0, datetimein) / 5) * 5, 0)
order by dateadd(minute, 5 + (datediff(minute, 0, datetimein) / 5) * 5, 0) desc

the problem in the result may i don't have any new record during 5 min.. i want to genrate the date with time.. ???
result :

(No column name)      (No column name)
2013-01-15 15:10:00.000      1
2013-01-15 14:45:00.000      2
2013-01-15 14:35:00.000      5
2013-01-15 14:30:00.000      1
2013-01-15 14:25:00.000      3
2013-01-15 14:20:00.000      1
2013-01-15 14:15:00.000      3
2013-01-15 14:10:00.000      1
2013-01-15 14:05:00.000      2
2013-01-15 13:55:00.000      2
2013-01-15 13:50:00.000      1
2013-01-15 13:45:00.000      2


maybe i will union all or cross join with generated

DECLARE
  @StartTime datetime = '2013-01-15 00:00:00',
  @EndTime datetime = '2013-01-16 00:00:00',
  @Interval int = 300;
SELECT
  StartTime = DATEADD(SECOND, (number - 1) * @Interval, @StartTime),
  EndTime   = DATEADD(SECOND, (number - 0) * @Interval, @StartTime),
  Duration  = @Interval
FROM master..spt_values
WHERE type = 'P'
  AND number BETWEEN 1 AND DATEDIFF(SECOND, @StartTime, @Endtime) / @Interval

UNION ALL

SELECT
  DATEADD(SECOND, -Duration, EndTime),
  EndTime,
  Duration
FROM (
  SELECT
    EndTime = @EndTime,
    Duration = DATEDIFF(SECOND, @StartTime, @Endtime) % @Interval
) s
WHERE Duration > 0

order by StartTime desc
0
 
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Accepted Solution

by:
afifosh earned 0 total points
ID: 38813580
SET ANSI_NULLS ON
GO

SET QUOTED_IDENTIFIER ON
GO


ALTER VIEW [dbo].[d]
AS
SELECT     DATEADD(SECOND, (number - 1) * 60, DATEADD(d, DATEDIFF(d, 0, GETDATE()), 0)) AS startd
FROM         master.dbo.spt_values
WHERE     (type = 'P') AND (DATEPART(hh, DATEADD(SECOND, (number - 1) * 60, DATEADD(d, DATEDIFF(d, 0, GETDATE()), 0))) BETWEEN DATEPART(hh, 
                      DATEADD(hh, - 3, GETDATE())) AND DATEPART(hh, GETDATE())) AND (DAY(DATEADD(SECOND, (number - 1) * 60, DATEADD(d, DATEDIFF(d, 0, 
                      GETDATE()), 0))) = DAY(GETDATE())) AND (DATEADD(SECOND, (number - 1) * 60, DATEADD(d, DATEDIFF(d, 0, GETDATE()), 0)) < GETDATE())


GO

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ALTER VIEW [dbo].[View_1]
AS
WITH dd AS (SELECT     DATEADD(mi, DATEDIFF(mi, 0, datetimein) + 1, 0) AS d, COUNT(1) AS sms
                            FROM         dbo.chat
                            WHERE     (datetimein BETWEEN DATEADD(minute, - 300, GETDATE()) AND GETDATE())
                            GROUP BY DATEADD(minute, DATEDIFF(mi, 0, datetimein) + 1, 0))
    SELECT     dbo.d.startd, ISNULL(dd_1.sms, 0) AS smscount
     FROM         dbo.d LEFT OUTER JOIN
                            dd AS dd_1 ON dd_1.d = dbo.d.startd

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Author Closing Comment

by:afifosh
ID: 38826229
i have test it and it work perfect :D
0

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