Split array in KSH

I need help in splitting an array into chunks.

I build an array from a file and echo the array content:

set -A array `grep $SRV_NAME /myfile| grep DBA| awk -F# '{print $4}'`
echo ${array[*]}

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The output is:

DBA1
DBA2
DBA3
DBA4

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When I count the array members, I however get only one member whereas I need to have 4.

print ${#array[*]} 

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Can you please show me how to solve this problem or what I am doing wrong. How can I split the array into chunks?
skahlert2010Asked:
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woolmilkporcConnect With a Mentor Commented:
Yes,

I'm well aware of what you're doing and what you're trying to achieve.

Remains my question:

With

echo ${array[*]}

do you really see the extracted values one per line?

That's the important part here! I tested using your data, and the result was as I expected:

K01TDB GRIDCTL READDB KT01STDB KT02STDB

and echo ${#array[*]}

gives "5".

(I substituted "SRV_NAME" with "DBA" because I didn't find another common element)

So your command works just fine for me. I still suspect there are weird characters in the inputfile.

Again: What do you see with "cat -v /myfile"?
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woolmilkporcCommented:
For some very strange reason there are linefeeds between the array elements.

Under normal circumstances this should not happen when using command substitution for array creation.

Could it be that "/myfile" contains some unusual characters, maybe because it came from a non-Unix machine?

Please examine this file, e.g. with "cat -v /myfile".
What do you see?
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skahlert2010Author Commented:
Hi woolmilkpork!

Don't be irritrated by the linefeed.

I didn't copy and paste the content.

This is the original content:

K01TDB
GRIDCTL
READDB
KT01STDB
KT02STDB

Any ideas?
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woolmilkporcCommented:
It's still the linefeeds!

The array elements should never appear each on a line of its own.
Or is this also a copy-and-paste thing?

You should rather see this:

K01TDB GRIDCTL READDB KT01STDB KT02STDB
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skahlert2010Author Commented:
These elements are grepped from different lines within the source file. They are not part on a single line!

The original output looks like:

1#K01TDB1#DBA#K01TDB
3#GRIDCTL1#DBA#GRIDCTL
4#READDB#DBA#READDB
5#KT01STDB1#DBA#KT01STDB
9#KT02STDB1#DBA#KT02STDB

With awk I cut of everything in front of the values.

From then on I don't know how to store these elements in an array individually.
I need to make a loop later on based on the values in that array.
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skahlert2010Author Commented:
Okay, I must have made a mistake since I am very new to shell skripting.

The following works for me:

set -A DBSIDS |\
for DBA_DBNAME in `grep $SRV_NAME /oracle/admin/config/dbaconf | grep DBA_DBNAME | awk -F# '{print $4}'`
do 
echo $DBA_DBNAME
done

print The array contains ${#DBSIDS[*]} elements!

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Output:

K01TDB
GRIDCTL
READDB
KT01STDB
KT02STDB

The array contains 5 elements!
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skahlert2010Author Commented:
Not the solution itself but made me try something that solved my problem!
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woolmilkporcCommented:
I never saw such a construct ("set -A xxx | something ...") before, and I couldn't reproduce any sensible effect.
What you see in DBSIDS[*] are old data from some previous attempts.

Anyway, thx for the points.
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