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# Boolean algebra

Posted on 2013-01-15
Medium Priority
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Hello,

how does this
``````(~b+~k+~b.~t+k.~t) . (t.~l+t.~k+l.~k)
``````
become this
``````~b.~k.t.~l  + ~b . ~k . t  +  ~b.~k.l  +  ~b.~t . l .~k
``````

I don't know how to say negative b so i use ~b
0
Question by:kensy11
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LVL 84

Expert Comment

ID: 38779401
Are you sure you wrote them correctly?
It looks like they are different for
b ~k l ~t
0

LVL 37

Accepted Solution

TommySzalapski earned 2000 total points
ID: 38779502
I agree that something isn't right. My guess is that one of the ~b terms should be b in the first expression otherwise ~b would consume ~b.~t

Try fully expanding it like you would in regular algebra with + and . like addition and multiplication.
Then cancel out any terms with b.~b etc. See if it looks closer.
0

LVL 32

Expert Comment

ID: 38785629
The 2nd expression has ~b in all four terms, so if b=T, then 2nd expression is F.
But, for b=T, the 1st expression can be T for some values of k, t, and l; so the two expressions are not the same.
0

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