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Boolean algebra

Posted on 2013-01-15
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Last Modified: 2013-04-22
Hello,

Can someone please help with this Boolean algebra:

how does this
(~b+~k+~b.~t+k.~t) . (t.~l+t.~k+l.~k)

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become this
~b.~k.t.~l  + ~b . ~k . t  +  ~b.~k.l  +  ~b.~t . l .~k

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I don't know how to say negative b so i use ~b
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Question by:kensy11
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3 Comments
 
LVL 84

Expert Comment

by:ozo
ID: 38779401
Are you sure you wrote them correctly?
It looks like they are different for
 b ~k l ~t
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Accepted Solution

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TommySzalapski earned 500 total points
ID: 38779502
I agree that something isn't right. My guess is that one of the ~b terms should be b in the first expression otherwise ~b would consume ~b.~t

Try fully expanding it like you would in regular algebra with + and . like addition and multiplication.
Then cancel out any terms with b.~b etc. See if it looks closer.
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LVL 32

Expert Comment

by:phoffric
ID: 38785629
The 2nd expression has ~b in all four terms, so if b=T, then 2nd expression is F.
But, for b=T, the 1st expression can be T for some values of k, t, and l; so the two expressions are not the same.
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