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case expression problem

Posted on 2013-01-16
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Last Modified: 2013-01-17
/* this code works,  similar version below does not */
/* some issue with the substr in the case statement*/

select a.bl_id, a.max_bl_id, substr(max_bl_id,5,4), a.title, a.name, m.location, m.description, m.bc_buildcode,
case when a.title = m.bc_buildcode then 'same'
    else 'diff'
    end as "fields same or different"
from bl A
join locations m
on a.title = m.bc_buildcode
order by name;


/*this code does not.  code is the same exception for the 1st line of the case */

select a.bl_id, a.max_bl_id, substr(max_bl_id,5,4), a.title, a.name, m.location, m.description, m.bc_buildcode,
case when substr(max_bl_id,5,4) like substr(m.bc_buildcode,1,4) then 'same'
    else 'diff'
    end as "fields same or different"
from bl A
join locations m
on a.title = m.bc_buildcode
order by name;
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Question by:stirus
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5 Comments
 
LVL 74

Accepted Solution

by:
sdstuber earned 400 total points
ID: 38784788
what doesn't work?

wrong results? no results? error? keyboard catches fire?


please provide sample data and expected results
0
 
LVL 74

Assisted Solution

by:sdstuber
sdstuber earned 400 total points
ID: 38784793
one question comes to mind immediately though.

Why do you use LIKE in the second query?  Are their wildcards in your strings? If not, it's effectively the same = and should be written that way to be self-documenting
0
 
LVL 23

Assisted Solution

by:paquicuba
paquicuba earned 200 total points
ID: 38784811
sdstuber is right, since you're extracting 4 characters from each string, you don't need to use the LIKE operator. However, if you're planning to extract 4 characters from the first string and 3 characters from the second one, then you can do something like:


select a.bl_id, a.max_bl_id, substr(max_bl_id,5,4), a.title, a.name, m.location, m.description, m.bc_buildcode,
case when substr(max_bl_id,5,4) like substr(m.bc_buildcode,1,3)||'%' then 'same'
    else 'diff'
    end as "fields same or different"
from bl A
join locations m
on a.title = m.bc_buildcode
order by name;
0
 
LVL 38

Assisted Solution

by:Geert Gruwez
Geert Gruwez earned 200 total points
ID: 38786066
if you want case insensitive check, then add upper() too

select a.bl_id, a.max_bl_id, substr(max_bl_id,5,4), a.title, a.name, m.location, m.description, m.bc_buildcode,
  decode(upper(substr(max_bl_id,5,4))=upper(substr(m.bc_buildcode,1,4)),'same','diff') 
  "fields same or different"
from bl A
join locations m
on a.title = m.bc_buildcode
order by name; 

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0
 

Author Closing Comment

by:stirus
ID: 38787546
My error.  comparing two unlike fields.  thanks for your response.
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