Solved

Problems reading xml node

Posted on 2013-01-17

1 solution

313 Views

Last Modified: 2013-01-17

I have a particular node that I'm trying to get to in the attached file.

I'm trying to use this code:

refPlanNodeList = xmlDemo.SelectNodes("PPMDResults/Results/patientlist/patient/refplanlist")
For Each refPlanNode In refPlanNodeList
refProv = refPlanNode.SelectSingleNode("refplan").Attributes("refprov").Value
If refProv.Replace("rprov", "") = physid Then
result = refPlanNode.SelectSingleNode("refplan/id").InnerText
End If
Next

I'm trying to loop through each refplan node but the above doesn't seem to work.
Demo.xml

Comment

Question by:rutledgj

[X]

Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

Help others & share knowledge
Earn cash & points
Learn & ask questions

Join The Community

3 Comments

LVL 35

Expert Comment

by:YZlat

ID: 387880672013-01-17

try this instead:

refPlanNodeList = xmlDemo.SelectNodes("PPMDResults/Results/patientlist/patient/refplanlist/refplan")
        For Each refPlanNode In refPlanNodeList
            refProv = refPlanNode.Attributes("refprov").Value
            If refProv.Replace("rprov", "") = physid Then
                result = refPlanNode.SelectSingleNode("refplan/id").InnerText
            End If
        Next

Open in new window

LVL 35

Expert Comment

by:YZlat

ID: 387880722013-01-17

instead of looping through refplan nodes you tried looping through refplanlist, and there is only one in your xml

LVL 35

Accepted Solution

by:YZlat

YZlat earned 400 total points

ID: 387880922013-01-17

disregard post above - i found one more isssue - the way you retrieve id attribute. Use

refPlanNodeList = xmlDemo.SelectNodes("PPMDResults/Results/patientlist/patient/refplanlist/refplan")
        For Each refPlanNode In refPlanNodeList
            refProv = refPlanNode.Attributes("refprov").Value
            If refProv.Replace("rprov", "") = physid Then ''physid Then
                result = refPlanNode.Attributes("id").Value
            End If
        Next

Open in new window

Featured Post

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Real Simple Syndication (RSS) with a Single PHP Script

Article by: Ray

The Client Need Led Us to RSS I recently had an investment company ask me how they might notify their constituents about their newsworthy publications. Probably you would think "Facebook" or "Twitter" but this is an interesting client. Their cons…

Key concepts of Delegate using C#

Article by: ROMA

It was really hard time for me to get the understanding of Delegates in C#. I went through many websites and articles but I found them very clumsy. After going through those sites, I noted down the points in a easy way so here I am sharing that unde…

How to see a live map of your network in NetCrunch network monitor

Video by: AdRem

In this video we outline the Physical Segments view of NetCrunch network monitor. By following this brief how-to video, you will be able to learn how NetCrunch visualizes your network, how granular is the information collected, as well as where to f…

display Triangles! and Circles! in a Microsoft Access Query -- Get Previous Record too

Video by: crystal

Visualize your data even better in Access queries. Given a date and a value, this lesson shows how to compare that value with the previous value, calculate the difference, and display a circle if the value is the same, an up triangle if it increased…