C++, copy constructor

Hello experts, please have a look at the following code:


#include <iostream>

using namespace std;

class Line
{
   public:
      int getLength( void );
      Line( int len );             // simple constructor, headers only
      Line( const Line &obj);      // copy constructor, headers only
      ~Line();                      // destructor

   private:
      int *ptr;
};

Line::Line(int len)
{
    cout << "Normal constructor allocating ptr" << endl;
    // allocate memory for the pointer;
    ptr = new int;
    *ptr = len;
}

Line::Line(const Line &obj)
{
    cout << "Copy constructor allocating ptr." << endl;
    ptr = new int;
   *ptr = *obj.ptr; // copy the value
}

Line::~Line(void)
{
    cout << "Freeing memory!" << endl;
    delete ptr;
}
int Line::getLength( void )
{
    return *ptr;
}

void display(Line obj)
{
   cout << "Length of line : " << obj.getLength() <<endl;
}

// Main function for the program
int main( )
{
   Line line(10);

   display(line);//****** why does it call copy constructor here? ******

   return 0;
}

I do not understand why calling 'display' with 'line' as argument makes a call to constructor here...

Any help?

Thank you

panJames
panJamesAsked:
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ambienceConnect With a Mentor Commented:
because

void display(Line obj)

does not take Line by reference. It takes it by value so a copy happens
0
 
ambienceCommented:
void display(Line& obj)

should not invoke the constructor.

Looking at the purpose of display its better to have it like

void display(const Line& obj)

but that wont compile unless you also change

int getLength( void ) const;

int Line::getLength( void ) const
{
    return *ptr;
}
0
 
ambienceCommented:
As a general rule, always consider passing objects as const references unless there is a compelling reason not to do so. Passing it by reference ensures there is no overhead of copying and const ensure there are no side-affects because you can only access const methods and data on the object.
0
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