Left Outer Join with only 1 result

Posted on 2013-01-18
Last Modified: 2013-01-18
I want to run a sql query using a left outer join, but I only want to return the first result, not all.

ParentID 2

Table 2:
ID1 ParentID2
ID2 ParentID2
ID3 ParentId2

So when the rows are joined we have:

ParentID 2& Id1 only, not ID2 and ID3.

How do I do that?

I want to check the null value of the Id1 column to see if there is a record in that table, but I definitely don't want my parent row to show up 3 times, just the once.

Question by:Starr Duskk
  • 3
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LVL 142

Expert Comment

by:Guy Hengel [angelIII / a3]
ID: 38793922
Please view his article 8806085321953
LVL 142

Assisted Solution

by:Guy Hengel [angelIII / a3]
Guy Hengel [angelIII / a3] earned 100 total points
ID: 38793929

Author Comment

by:Starr Duskk
ID: 38794032
that doesn't help.

A DISTINCT won't work because the value of the joined table's primary ID field is going to be unique.

I also don't see how a group by is going to resolve this.

Do you or anyone have any specific solutions to my problem?

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LVL 142

Expert Comment

by:Guy Hengel [angelIII / a3]
ID: 38794040
the "ROWNUMBER()" method will work, and that is exactly what the article is about :)

Author Comment

by:Starr Duskk
ID: 38794050
I feel I'm on a wild goose chase. I don't find any code in there using a JOIN and the snippet they have for mssql server doesn't show a row number. So unless you can dredge out of that article a snippet for me that works, I'm not closing this.
LVL 26

Accepted Solution

Chris Luttrell earned 400 total points
ID: 38794135
This is what andelIII is trying to show you in his article, you end up with something like this where you use the ROW_NUMBER() function to assign a rank (the row_number) per grouping (the Partition) to your secondary table so that when you join to it, you can match on just the first value.
SELECT * -- Pick the columns you want to see here
FROM dbo.Table1 T
				FROM dbo.Table2 T2) T2 ON T.ParentID = T2.ParentID AND rn = 1

Open in new window

You get results like this (I put an ID of 1 with no children to show it works both with and without child records)

Author Closing Comment

by:Starr Duskk
ID: 38794553
Thanks for all the additional effort!

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