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Config Cisco 2900 router for AT&T T1 circuit

Posted on 2013-01-18
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Last Modified: 2013-01-18
So I am setting up a new Cisco 2900 router for a site and AT&T is providing the T1 circuit. I need to config this router but I haven't done one in years and was wondering if someone can assist. Below is the info from AT&T but I am confuse on what IP's to use for the s1 int and fe0/0 int. And if there is anything else I need to add....

Configuration Details:
>
> IP Classless: in global configuration
>
> LBO: 0.0 (If cat 5 cable < 50 ft. (default in most units), if > next
>
> setting (7.5)
>
> Line Coding: B8ZS (Bipolar 8 zeros substitution)
>
> Net Signal: ESF (Extended Super Frame)
>
> Port Base Rate: 64K (1 ch = 56k or 64k each channel)
>
>
>
> Equipment Information:
>
> Equipment Provider: Customer
>
> Installation Type: Tele-Install
>
> Timing: Net (from Network)
>
> Encapsulation: PPP
>
> Routing Protocol:Static
>
> Port Speed:1544
>
> VoIP Media Address:
>
> VoIP Signaling Address:
>
>
> IP Address Block
>
> IP Address: x.x.211.160/29
>
>
> WAN Link Details:
>
> WAN Link IP Address:x.x.222.164
>
> WAN Link IPV4 Reference Address:N/A
>
> AR Serial INT IP Address:x.x.222.165
>
> CR Serial INT IP Address:x.x.222.166
>
> WAN Link Subnet Mask:255.255.255.252
>
>
>
>
> Circuit Details:
>
> Access Circuit Identifier:.DHEC.291140..ATI..
>
> Service Circuit Identifier:.DHEC.291140..ATI..
>
> Channel Allocation:
>
> Domains :
>
> Domain Name:
>
> Primary Server:
>
> IPv6 Primary Server:
>
>
> Secondary DNS:
>
> Secondary Server:
>
> IPv6 Secondary Server
>
>
> Internet Services :
>
> Internet Service:
>
>
> LAN Information:
>
> IP Address:x.x.211.160/29
>
> LAN/Ethernet/Gateway IP Address:
>
> Broadcast IP Address:
>
> Subnet Mask:29
>
>
>
>
> BIB Device Type
>
> BIB Base Unit Type:
>
> Quantity of 8 Port PoE Device: 0
>
> Quantity of 24 Port PoE Device: 0
>
> Router name:
>
> Router model:
>
> Swap Router name:
>
> Swap Router Model:


Thanks...
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Question by:clynch302
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Accepted Solution

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Don Johnston earned 500 total points
ID: 38794808
CR=Customer Router

So your provider facing interface would be x.x.222.166/30

x.x.211.160/29 would be your inside network so you could use any address from x.x.211.161-166
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Author Comment

by:clynch302
ID: 38794866
So my s0/0 would be x.x.222.166 255.255.255.252
and my f0/0 would be x.x.211.161 255.255.255.248

and my route would be 0.0.0.0 0.0.0.0 x.x.x.222.165

Is that right?
0
 
LVL 50

Expert Comment

by:Don Johnston
ID: 38794879
Yep.
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Author Closing Comment

by:clynch302
ID: 38794881
Thanks. I was a bit rusty.
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