Solved

Bracket Turmoil!

Posted on 2013-01-19
4
244 Views
Last Modified: 2013-01-19
I have code that works as one piece.
$(document).ready(function()
{
	
$(".Doggie").change(function()
{
	var LocationString ='Rid='+ $(this).val();
    $.ajax({
        type: "POST",
        url: "place_city.php",
        data: LocationString,
		cache: false,
        success: function (html) {
            $(".Kitty").html(html);
        }
    });
});

$('.Kitty').live("change",function(){
	var Rid = $('#Doggie').val(),  // This is the value of the id="Doggie" selected option
    Cid = $(this).val(); // This is the value of the id="Kitty" selected option

	$.ajax({
        type: "POST",
        url: "place_area.php",
        data: {"Rid":Rid,"Cid":Cid}, 
        cache: false,
        success: function (html) {
								   
$(".Pig").html(html);
} 
});
});
});

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However;
I needed to seperate it.  The first part works well.
$(document).ready(function()
	{
	$("#Doggie").change(function()
	{
	var LocationString ='Rid='+ $(this).val();
    		$.ajax({
        		type: "POST",
        		url: "place_city.php",
        		data: LocationString,
		cache: false,
        		success: function (html) {
            	                 $("#Kitty").html(html);
        		}
    		});
		});
    		});

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But the second part, I am having difficulty with the brackets.  Any help appreciated.  Thank you.
$(document).ready(function()
{
$("#Kitty").live("change",(function()
{
var Rid = $('#Doggie').val(),
Cid = $(this).val();
$.ajax({
	type: "POST",
	url: "place_area.php",
	data: {"Rid":Rid,"Cid":Cid},
	cache: false,
	success: function (html) {
	$("#Pig").html(html);
	}
});
});
});

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0
Comment
Question by:DS928
  • 2
  • 2
4 Comments
 
LVL 82

Expert Comment

by:leakim971
ID: 38797649
why do you need to split it?
0
 
LVL 82

Accepted Solution

by:
leakim971 earned 500 total points
ID: 38797653
anyway.. here the second part :
<script type="text/javascript">
	$(document).ready(function() {
		$("#Kitty").live("change",function() {
			var Rid = $('#Doggie').val(),
			Cid = $(this).val();
			$.ajax({
				type: "POST",
				url: "place_area.php",
				data: {"Rid":Rid,"Cid":Cid},
				cache: false,
				success: function (html) {
					$("#Pig").html(html);
				}
			});
		});
	});
</script>

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0
 

Author Comment

by:DS928
ID: 38797685
Because its running off of a switch.  And the criteria is different for each search..You've been to the site I'm building.  I have the five buttons and three listboxes with different searchs, so I'm using a switch to direct the different options.  Thank you for your help!
0
 

Author Closing Comment

by:DS928
ID: 38797687
Clear, Concise and very helpful!
0

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