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Rebulit index for all table in all SQL server 2005 database

Posted on 2013-01-21
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Last Modified: 2013-03-06
Dear all,

Any script for me to rebuilt index for all index of all table in all database?

I want to do it all in one file.

I am using SQL server 2005.

DBA100.
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Question by:marrowyung
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by:James Murrell
James Murrell earned 100 total points
ID: 38800442
EXEC sp_MSforeachtable @command1="print '?' DBCC DBREINDEX ('?', ' ', 80)"
 GO


should help its what i use
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by:marrowyung
ID: 38800452
The following script should be run without any problem (e.g. : accidently delete/modify any data)

Any one script can do the job for all user database ?



SET NOCOUNT ON;
DECLARE @objectid int;
DECLARE @indexid int;
DECLARE @partitioncount bigint;
DECLARE @schemaname nvarchar(130);
DECLARE @objectname nvarchar(130);
DECLARE @indexname nvarchar(130);
DECLARE @partitionnum bigint;
DECLARE @partitions bigint;
DECLARE @frag float;
DECLARE @command nvarchar(4000);
-- Conditionally select tables and indexes from the sys.dm_db_index_physical_stats function
-- and convert object and index IDs to names.
SELECT
    object_id AS objectid,
    index_id AS indexid,
    partition_number AS partitionnum,
    avg_fragmentation_in_percent AS frag
INTO #work_to_do
FROM sys.dm_db_index_physical_stats (DB_ID(), NULL, NULL , NULL, 'LIMITED')
WHERE avg_fragmentation_in_percent > 10.0 AND index_id > 0;
-- Declare the cursor for the list of partitions to be processed.
DECLARE partitions CURSOR FOR SELECT * FROM #work_to_do;
-- Open the cursor.
OPEN partitions;
-- Loop through the partitions.
WHILE (1=1)
    BEGIN;
        FETCH NEXT
           FROM partitions
           INTO @objectid, @indexid, @partitionnum, @frag;
        IF @@FETCH_STATUS < 0 BREAK;
        SELECT @objectname = QUOTENAME(o.name), @schemaname = QUOTENAME(s.name)
        FROM sys.objects AS o
        JOIN sys.schemas as s ON s.schema_id = o.schema_id
        WHERE o.object_id = @objectid;
        SELECT @indexname = QUOTENAME(name)
        FROM sys.indexes
        WHERE  object_id = @objectid AND index_id = @indexid;
        SELECT @partitioncount = count (*)
        FROM sys.partitions
        WHERE object_id = @objectid AND index_id = @indexid;
-- 30 is an arbitrary decision point at which to switch between reorganizing and rebuilding.
        IF @frag < 30.0
              SET @command = N'ALTER INDEX ' + @indexname + N' ON ' + @schemaname + N'.' + @objectname + N' REORGANIZE';
        IF @frag >= 30.0
            SET @command = N'ALTER INDEX ' + @indexname + N' ON ' + @schemaname + N'.' + @objectname + N' REBUILD';
        IF @partitioncount > 1
                    SET @command = @command + N' PARTITION=' + CAST(@partitionnum AS nvarchar(10));
                            EXEC (@command);
        --PRINT N'Executed: ' + @command;
    END;
-- Close and deallocate the cursor.
CLOSE partitions;
DEALLOCATE partitions;
-- Drop the temporary table.
DROP TABLE #work_to_do;
GO
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by:James Murrell
ID: 38800455
The one i posted
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Accepted Solution

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Anthony Perkins earned 400 total points
ID: 38801890
Any script for me to rebuilt index for all index of all table in all database?
...
WHERE avg_fragmentation_in_percent > 10.0 AND index_id > 0;

I am confused you ask for code to rebuild all tables in all databases and then post a script that only does it for tables that are fragmented by a certain amount.

So if you want the first go with the first solution posted by cs97jjm3, except that it needs to be included in another undocumented function sp_msforeachdb to do all databases.

If on the other hand you want to only do those tables that have fragmented indexes then download and install the scripts from here:
http://ola.hallengren.com/sql-server-index-and-statistics-maintenance.html

And then your script becomes as simple as the first example:
EXECUTE dbo.IndexOptimize
@Databases = 'ALL_DATABASES',
@FragmentationLow = NULL,
@FragmentationMedium = 'INDEX_REORGANIZE,INDEX_REBUILD_ONLINE,INDEX_REBUILD_OFFLINE',
@FragmentationHigh = 'INDEX_REBUILD_ONLINE,INDEX_REBUILD_OFFLINE',
@FragmentationLevel1 = 5,
@FragmentationLevel2 = 30

Open in new window

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Author Comment

by:marrowyung
ID: 38813235
acperkins,

"EXECUTE dbo.IndexOptimize
@Databases = 'ALL_DATABASES',
@FragmentationLow = NULL,
@FragmentationMedium = 'INDEX_REORGANIZE,INDEX_REBUILD_ONLINE,INDEX_REBUILD_OFFLINE',
@FragmentationHigh = 'INDEX_REBUILD_ONLINE,INDEX_REBUILD_OFFLINE',
@FragmentationLevel1 = 5,
@FragmentationLevel2 = 30 "

Yeah, that one is listed as the example. It works for you, right?
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Author Comment

by:marrowyung
ID: 38956917
it seems that running this:

use <userdatabase>

EXECUTE dbo.IndexOptimize
@Databases = 'ALL_DATABASES',
@FragmentationLow = NULL,
@FragmentationMedium = 'INDEX_REORGANIZE,INDEX_REBUILD_ONLINE,INDEX_REBUILD_OFFLINE',
@FragmentationHigh = 'INDEX_REBUILD_ONLINE,INDEX_REBUILD_OFFLINE',
@FragmentationLevel1 = 5,
@FragmentationLevel2 = 30

the avg fragmentation_in_precent still the same, checking by this:
SELECT DB_NAME(a.database_id) as [Database Name]
            ,OBJECT_NAME(SO.id) as [Table Name]
            ,a.object_id as [Table Object ID]
            ,b.name as [Index Name]
            ,a.index_id
            ,a.avg_fragmentation_in_percent
FROM sys.dm_db_index_physical_stats (DB_ID(), NULL, NULL, NULL, NULL) AS a
    JOIN sys.indexes AS b
      ON a.object_id = b.object_id
      JOIN sys.sysobjects AS SO
      on b.object_id = SO.id
      AND a.index_id = b.index_id
where a.database_id = db_id() and SO.xtype = 'U'
order by a.avg_fragmentation_in_percent DESC
GO

any reason ?
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Expert Comment

by:Anthony Perkins
ID: 38960265
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