asked on

SUM for SQL Query, Grouping and an OTHER column

Hello experts:
Suppose this is my data: "AnimalName" is a column name in my table called "myAnimals" and contains the following values:

Bird
Cat
Dog
Turtle
Turtle
Bird
Bird
Cat
Dog
Elephant
Cat
Cat
Dog
Bird
Cat
Turtle
Giraffe
Elephant
Dog

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I want to count the groups, but lump Giraffes and Elephants into a new group called OTHER. Also, I want to sum up everything. The output for the query should look like this:
ALL 19
Bird 4
Cat 5
Dog 4
Turtle 3
Other 3

I can do this:

 SELECT AnimalName, COUNT(*) as "COUNT" from myAnimals where AnimalName in ('Bird','Dog','Cat','Turtle') group by AnimalName

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I can't figure out how to get the OTHER.
Hope this makes sense! Thanks!

Christopher Gordon

Try using a CASE statement

select

      case AnimalName
       when 'Giraffes' then 'Other'
       when 'Elephants' then 'Other'
       else AnimalName
      end as myAnimalName

from myAnimals

group by case AnimalName
       when 'Giraffes' then 'Other'
       when 'Elephants' then 'Other'
       else AnimalName
      end

Christopher Gordon

Oh, I missed the COUNT(*) as the_Count as an additional field in select.

Patrick Matthews

And to get the 'all':

select 

      case AnimalName
         when 'Giraffes' then 'Other'
         when 'Elephants' then 'Other'
         else AnimalName
      end as myAnimalName,
    COUNT(1) AS Count
from myAnimals

group by case AnimalName
         when 'Giraffes' then 'Other'
         when 'Elephants' then 'Other'
         else AnimalName
      end
union all
SELECT 'ALL' as myAnimalName, COUNT(1) as Count
FROM myAnimals
ORDER BY 2 DESC, 1 ASC

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SOLUTION

Christopher Gordon

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ASKER CERTIFIED SOLUTION

Chris Luttrell

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Scott Pletcher

Careful -- if you add an "Aardvark", the previous code no longer puts "All" first.

CREATE TABLE #Animal (AnimalName VARCHAR(50));
INSERT INTO #Animal ( AnimalName )
VALUES
('Aardvark'),
('Bird'),
('Cat'),
('Dog'),
('Turtle'),
('Turtle'),
('Bird'),
('Bird'),
('Cat'),
('Dog'),
('Elephant'),
('Cat'),
('Cat'),
('Dog'),
('Bird'),
('Cat'),
('Turtle'),
('Giraffe'),
('Elephant'),
('Dog')

SELECT ISNULL(CASE A.AnimalName WHEN 'Elephant' THEN 'Other' WHEN 'Giraffe' THEN 'Other' ELSE A.AnimalName END, 'All') AnimalName, COUNT(*) Count
FROM #Animal A
GROUP BY CASE A.AnimalName WHEN 'Elephant' THEN 'Other' WHEN 'Giraffe' THEN 'Other' ELSE A.AnimalName END
WITH ROLLUP
ORDER BY GROUPING ( CASE A.AnimalName WHEN 'Elephant' THEN 'Other' WHEN 'Giraffe' THEN 'Other' ELSE A.AnimalName END ) DESC, AnimalName

DROP TABLE #Animal

Chris Luttrell

Good catch Scott, we all get caught up with false assumtions with the data we are playing with.

I took it one step further and added a line so it will also sort 'Other' to the end of the list

SELECT ISNULL(CASE A.AnimalName WHEN 'Elephant' THEN 'Other' WHEN 'Giraffe' THEN 'Other' ELSE A.AnimalName END, 'All') AnimalName, COUNT(*) Count
FROM #Animal A
GROUP BY CASE A.AnimalName WHEN 'Elephant' THEN 'Other'  WHEN 'Giraffe' THEN 'Other' ELSE A.AnimalName END
WITH ROLLUP
ORDER BY GROUPING ( CASE A.AnimalName WHEN 'Elephant' THEN 'Other'  WHEN 'Giraffe' THEN 'Other' ELSE A.AnimalName END ) DESC, 
MIN(CASE A.AnimalName WHEN 'Elephant' THEN 2  WHEN 'Giraffe' THEN 2 ELSE 1 END), 
AnimalName

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awking00

select 'ALL' as groupname, count(*) cnt from myanimals
union all
select replace(replace(animalname,'Giraffe','Other'),'Elephant','Other'), count(*)
from myanimals group by replace(replace(animalname,'Giraffe','Other'),'Elephant','Other')
;