PHP printing CSS error question

Hi everyone,

I know it's not the best practice but we need to print some CSS inside PHP like this

if ( $remind_status == 1 )
	{
		echo "<br><span style="padding:0 0 0 30px;
border-left:#0066cc 12px solid;
background-color:#3FA9F5;
padding:8px;
color:#FFF;
-webkit-border-radius: 0px 6px 6px 0px;
border-radius: 0px 6px 6px 0px;margin-left:30px;">You have an active reminder for every $remind_days days of inactivity!</span>";
	}

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but it's giving the following error:

Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in /home/clear555/public_html/jstats.php on line 339 (line that starts with echo)

Could anyone tell us what we're doing wrong here?

Thanks,

D
TLN_CANADAAsked:
Who is Participating?
 
rgranlundConnect With a Mentor Commented:
it is your use of apostrophe's.
use this:

<?php
if ( $remind_status == 1 )
	{
		echo '<br><span style="padding:0 0 0 30px;
border-left:#0066cc 12px solid;
background-color:#3FA9F5;
padding:8px;
color:#FFF;
-webkit-border-radius: 0px 6px 6px 0px;
border-radius: 0px 6px 6px 0px;margin-left:30px;">You have an active reminder for every $remind_days days of inactivity!</span>';
	}
?>

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0
 
rgranlundCommented:
Thanks for the points and glad I was able to help.
0
 
TLN_CANADAAuthor Commented:
Thank you, one other small question with it if I may. The variable $remind_days inside the code is only printing as I guess it thinks its text inside this block. How could I adjust this so it prints the PHP variable here?
0
 
rgranlundCommented:
You concantonate:
<?php
if ( $remind_status == 1 )
      {
            echo '<br><span style="padding:0 0 0 30px;
border-left:#0066cc 12px solid;
background-color:#3FA9F5;
padding:8px;
color:#FFF;
-webkit-border-radius: 0px 6px 6px 0px;
border-radius: 0px 6px 6px 0px;margin-left:30px;">You have an active reminder for every' . $remind_days.  'days of inactivity!</span>';
      }
?>
0
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