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SQL function compare variable to a string

Posted on 2013-01-23
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Last Modified: 2013-01-23
How can I find the correct row when the variable is one character that exists within the field and the field is many characters?

c.gpatypes = OMCG
@gpatypec = 'M'

normally I would find the row with:
select * from c where gpatypes like '%m%'

but the function isn't working with
gpatypes like '%@gpatypec%'
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Question by:dwiseman3
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Guy Hengel [angelIII / a3] earned 250 total points
ID: 38811488
Like '%' + @var + '%'
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by:Jim Horn
Jim Horn earned 250 total points
ID: 38811502
^^^ what he said

Also, this will return the character number of the first instance of @gpatypec, so a zero would mean it's not there...

CHARINDEX(c.gpatypes, @gpatypec, 1) > 0
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