Still celebrating National IT Professionals Day with 3 months of free Premium Membership. Use Code ITDAY17

x
?
Solved

regexp_count not working

Posted on 2013-01-23
9
Medium Priority
?
2,710 Views
Last Modified: 2013-01-24
I created a view called v with column called string;

--this works
select string from v;

returns:
www.oracle-developer.net

--problem
SELECT REGEXP_COUNT(string, 'e') AS "e Count"
    FROM   v;

why do I get error:
ORA-00904: "REGEXP_COUNT": invalid identifier
0
Comment
Question by:claghorn
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 3
  • 3
  • 2
  • +1
9 Comments
 
LVL 77

Expert Comment

by:slightwv (䄆 Netminder)
ID: 38812022
What is your database version?
I believe regex_count is new in 11g.
0
 
LVL 77

Expert Comment

by:slightwv (䄆 Netminder)
ID: 38812032
The 10gR2 docs only show:
REGEXP_INSTR
REGEXP_REPLACE
REGEXP_SUBSTR


http://docs.oracle.com/cd/B19306_01/server.102/b14200/toc.htm
0
 
LVL 77

Assisted Solution

by:slightwv (䄆 Netminder)
slightwv (䄆 Netminder) earned 508 total points
ID: 38812042
The 11gR1 docs have it:
REGEXP_COUNT
REGEXP_INSTR
REGEXP_REPLACE
REGEXP_SUBSTR

http://docs.oracle.com/cd/B28359_01/server.111/b28286/toc.htm
0
Concerto's Cloud Advisory Services

Want to avoid the missteps to gaining all the benefits of the cloud? Learn more about the different assessment options from our Cloud Advisory team.

 
LVL 74

Expert Comment

by:sdstuber
ID: 38812079
slightwv is correct, regexp_count is only available in 11g and above.

you can however, write your own....

Here's a simplified version, it simply looks for expressions within a string but I didn't include the position and match param  options



CREATE OR REPLACE FUNCTION myregexp_count(p_string IN VARCHAR2, p_expression IN VARCHAR2)
    RETURN INTEGER
IS
    v_cnt      INTEGER := 0;
    v_string   VARCHAR2(32767) := p_string;
BEGIN
    WHILE REGEXP_INSTR(v_string, p_expression) > 0
    LOOP
        v_string  := REGEXP_REPLACE(v_string, p_expression, null,1, 1);
        v_cnt     := v_cnt + 1;
    END LOOP;

    RETURN v_cnt;
END;
0
 
LVL 74

Expert Comment

by:sdstuber
ID: 38812088
this is a more complete version that supports the position and match param options



CREATE OR REPLACE FUNCTION myregexp_count(p_string        IN VARCHAR2,
                                          p_expression    IN VARCHAR2,
                                          p_position      IN INTEGER DEFAULT 1,
                                          p_match_param   IN VARCHAR2 DEFAULT NULL
                                         )
    RETURN INTEGER
IS
    v_cnt      INTEGER := 0;
    v_string   VARCHAR2(32767) := SUBSTR(p_string, p_position);
BEGIN
    WHILE REGEXP_INSTR(v_string,
                       p_expression,
                       1,
                       1,
                       0,
                       p_match_param
                      ) > 0
    LOOP
        v_string      :=
            REGEXP_REPLACE(v_string,
                           p_expression,
                           NULL,
                           1,
                           1,
                           p_match_param
                          );
        v_cnt  := v_cnt + 1;
    END LOOP;

    RETURN v_cnt;
END;
0
 
LVL 74

Accepted Solution

by:
sdstuber earned 512 total points
ID: 38812148
more efficient version of above - no need to do the replace, just increment the occurence counter on the instr



CREATE OR REPLACE FUNCTION myregexp_count(p_string        IN VARCHAR2,
                                           p_expression    IN VARCHAR2,
                                           p_position      IN INTEGER DEFAULT 1,
                                           p_match_param   IN VARCHAR2 DEFAULT NULL
                                          )
    RETURN INTEGER
IS
    v_cnt   INTEGER := 0;
BEGIN
    WHILE REGEXP_INSTR(p_string,
                       p_expression,
                       p_position,
                       v_cnt + 1,
                       0,
                       p_match_param
                      ) > 0
    LOOP
        v_cnt  := v_cnt + 1;
    END LOOP;

    RETURN v_cnt;
END;
0
 
LVL 32

Expert Comment

by:awking00
ID: 38815109
claghorn, you're showing Oracle 11g as a tag. Are you really using 11g? If so, there's no reason that regexp_count shouldn't work. How are you submitting the query?
0
 
LVL 32

Expert Comment

by:awking00
ID: 38815119
Works for me -
SQL> create view v(string) as select 'www.oracle-developer.net' from dual;

View created.

SQL> select * from v;

STRING
------------------------
www.oracle-developer.net

SQL> select regexp_count(string,'e') as "e Count" from v;

   e Count
----------
         5
0
 

Author Closing Comment

by:claghorn
ID: 38816117
I thought I was on 11g but it was 10g. Thanks for the workaround as an extra.
0

Featured Post

Hire Technology Freelancers with Gigs

Work with freelancers specializing in everything from database administration to programming, who have proven themselves as experts in their field. Hire the best, collaborate easily, pay securely, and get projects done right.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Working with Network Access Control Lists in Oracle 11g (part 1) Part 2: http://www.e-e.com/A_9074.html So, you upgraded to a shiny new 11g database and all of a sudden every program that used UTL_MAIL, UTL_SMTP, UTL_TCP, UTL_HTTP or any oth…
How to Unravel a Tricky Query Introduction If you browse through the Oracle zones or any of the other database-related zones you'll come across some complicated solutions and sometimes you'll just have to wonder how anyone came up with them.  …
This video explains at a high level with the mandatory Oracle Memory processes are as well as touching on some of the more common optional ones.
This video shows how to copy an entire tablespace from one database to another database using Transportable Tablespace functionality.

715 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question