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Right 7 of sequence unless end alpha

Ok I have characters like this: CG125BR8114662 OR CG125BR8114662D

I would like the right 7 if no end alpha character exists or if end alpha exists then the same without the end alpha.

I tried:
right(
trim(
iif(
NOT isnumeric(right([VIN],1),
left([VIN],len([VIN])-1),
[VIN])
)
,
7)

I am in access query grid
0
PeterBaileyUk
Asked:
PeterBaileyUk
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2 Solutions
 
mbizupCommented:
try this:

Right(iif(ISNumeric(Right(VIN,1) = True, VIN, LEFT(VIN, Len(VIN) -1)),7)

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mbizupCommented:
Opps - Missed a ):

Right(iif(ISNumeric(Right(VIN,1)) = True, VIN, LEFT(VIN, Len(VIN) -1)),7)

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0
 
Rey Obrero (Capricorn1)Commented:
try this

Right(IIf(Not IsNumeric(Right([VIN],1)),Left([VIN],Len([Vin])-1),[VIN]),7)
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PeterBaileyUkAuthor Commented:
its failing on arguments
0
 
mbizupCommented:
Try this again... This seems to test okay in VBA:

Right(iif(ISNumeric(Right(VIN,1) = True, VIN, LEFT(VIN, Len(VIN) -1)),7)
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mbizupCommented:
Also,  if VIN can be null or less than 7 letters:


IIF(Len(VIN & "") < 7, "VIN Too Short", Right(iif(ISNumeric(Right(VIN,1) = True, VIN, LEFT(VIN, Len(VIN) -1)),7))

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0
 
PeterBaileyUkAuthor Commented:
thx
0
 
mbizupCommented:
Correction:

IIF(LEN(VIN & "") < 7, "VIN Too Short",  Right(iif(  ISNumeric(Right(VIN,1)) = True, VIN, LEFT(VIN, Len(VIN) -1)),7))

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0
 
mbizupCommented:
Can you try my comment at http:#a38814276 again?

It works identically to the later one that you selected from Capricorn1  (they are equivalent syntaxes)
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PeterBaileyUkAuthor Commented:
I will try the other too i noticed also that the result sometimes gives an alpha at the start of the solution. it would be better if the result didnt contain an alpha at the beginning. ex: C122502

the ultimate goal will be to sort the sequence numbers from a min and a max.
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PeterBaileyUkAuthor Commented:
i can always post a new question re stripping the front or any alpha from result @mbizup as i notice i didnt distribute the points sorry.
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mbizupCommented:
Both solutions will simply give you the right-most 7 characters without a trailing non-numeric character .. that was based on the wording of your original post.

However, if you want to strip out an unknown number of alpha characters from both the beginning and the end, you might have to use VBA.  Check out the solution here:
http://www.utteraccess.com/forum/Removing-alphanumeric-ch-t1898931.html

That removes non-numbers, leaving behind a numeric string that can be any length.

Edit --
Sorry.. I'm misreading that one it removes non-alpha numeric characters, but you can adjust the criteria used in he code to exclude anything out that is not a number (Ascii values between 48 and 57)
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PeterBaileyUkAuthor Commented:
the criteria at first was correct, i dont know if stripping out an alpha in the middle or elsewhere will serve purpose. any number upto 7 numerals could be surrounded by alpha so the left and right alpha is all i want to remove. the numeral part will be the serial number of the vehicle, if i get a vin with a character in the middle of that number the vin is wrong so i wouldnt filter on that.

I wonder if the code can be honed to strip the left if one exists after the first removal without excessive actions
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mbizupCommented:
Thats doable, but it will only cover one character to the left and one to the right.  The expression would also get quite complicated, so I'd suggest using a VBA function:

Function GetNum(VIN)
   Dim sFirst As String
   GetNum = Right(IIf(IsNumeric(Right(VIN, 1)) = True, VIN, Left(VIN, Len(VIN) - 1)), 7)
   sFirst = Left(GetNum, 1)
   GetNum = IIf(IsNumeric(sFirst) = True, GetNum, Right(GetNum, Len(GetNum) - 1))
End Function

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and call it from your query:

SELECT GetNum(VIN) AS ModifiedVIN
FROM...

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