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regexp_substr to get multiple strings from one

Posted on 2013-01-25
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Last Modified: 2013-01-25
I've been trying to get both 'string one' and 'string two' returned to me from this query.
Can it be done?
I can get one or the other but not both.
select regexp_substr('string one, string two', '[^,]+',1,1) from dual;
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Question by:claghorn
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Expert Comment

by:paquicuba
ID: 38819145
Are you trying to get rid of the comma, just replace it:

select replace('string one, string two', ',') from dual;
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Author Comment

by:claghorn
ID: 38819156
no, I want two rows returned.
string one
string two
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Expert Comment

by:sdstuber
ID: 38819173
search EE for str2tbl


select * from table(str2tbl('string one,string two'))
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Assisted Solution

by:sdstuber
sdstuber earned 200 total points
ID: 38819181
or using built ins

SELECT     REGEXP_SUBSTR(s, '[^,]+', 1, LEVEL)
      FROM (SELECT 'string one, string two' s FROM DUAL)
CONNECT BY LEVEL <= REGEXP_COUNT(s, '[^,]+')


or, if you know you'll always have 2 values

SELECT     REGEXP_SUBSTR('string one, string two', '[^,]+', 1, LEVEL)
      FROM DUAL
CONNECT BY LEVEL <= 2;
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Accepted Solution

by:
sdstuber earned 200 total points
ID: 38819197
another method if you don't have regexp_count but don't know how many elements there will lbe


SELECT     REGEXP_SUBSTR(s, '[^,]+', 1, LEVEL)
      FROM (SELECT 'string one, string two' s FROM DUAL)
CONNECT BY LEVEL <= LENGTH(s) - LENGTH(REPLACE(s, ',')) + 1
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Expert Comment

by:sdstuber
ID: 38819206
you may want to put a trim around the results if you have extra spaces around the comma delimiters


select  TRIM( REGEXP_SUBSTR(s, '[^,]+', 1, LEVEL) ) .....
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LVL 23

Expert Comment

by:paquicuba
ID: 38819225
Just in case what you want are two rows but within the same string, do this:

select regexp_replace('string one, string two',', *',chr(10)) from dual;
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