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MySQL CONCAT problems

Posted on 2013-01-25
2
Medium Priority
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Last Modified: 2013-01-25
I am trying to output the results of this query.  I have been playing around with it all day.  I am getting results except for the CONCAT field, Here is the query.

$query="SELECT tblRestaurants.RestName,
CONCAT(tblLocations.StreetNumber,' ', tblLocations.Street)
FROM tblRestaurants INNER JOIN tblLocations ON tblRestaurants.RestID = tblLocations.RestID
	WHERE tblLocations.CuisineID='$Doggie'
	GROUP BY tblLocations.RestID and tblRestaurants.RestName
	ORDER BY tblRestaurants.RestName ASC";

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and the results...
<?php
$i=0;
while ($i < $num) {
$f1=mysql_result($result,$i,"RestName");
$f2=mysql_result($result,$i,"[CONCAT(tblLocations.StreetNumber,'  ', tblLocations.Street)]");
?>

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It has to be in the syntax?
0
Comment
Question by:DS928
2 Comments
 
LVL 143

Accepted Solution

by:
Guy Hengel [angelIII / a3] earned 2000 total points
ID: 38819719
you have to give the expression an alias, and use the alias in php:
$query="SELECT tblRestaurants.RestName,
CONCAT(tblLocations.StreetNumber,' ', tblLocations.Street) street_info
FROM tblRestaurants INNER JOIN tblLocations ON tblRestaurants.RestID = tblLocations.RestID
	WHERE tblLocations.CuisineID='$Doggie'
	GROUP BY tblLocations.RestID and tblRestaurants.RestName
	ORDER BY tblRestaurants.RestName ASC";

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and then:
<?php
$i=0;
while ($i < $num) {
$f1=mysql_result($result,$i,"RestName");
$f2=mysql_result($result,$i,"street_info");
?>

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http://www.experts-exchange.com/Database/Miscellaneous/A_11135-Why-should-I-use-aliases-in-my-queries.html
0
 

Author Closing Comment

by:DS928
ID: 38819737
Spot on!
0

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