Want to protect your cyber security and still get fast solutions? Ask a secure question today.Go Premium

x
  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 541
  • Last Modified:

How to get the first row of a Matrix with LINQ

Hello everyone,
               I need to see if the pallet is stackable or not. If I get two pallets the following LINQ work fine but if we have only one pallet with information does not work.

 var stackableUDC = (from ms in Model.CurrentMissions
                                where (ms.CurrentStationId == StationId 
                                && ms.Lgv.Station.Positions.Select(y =>  y.TrackingId > 0 
                                                                    && y.TrackingInfo.StackableType > 0
                                                                    && y.TrackingInfo.StackableType == (int)EStackableType.doubleStack
                                                                    && y.TrackingInfo.StackableType != (int)EStackableType.singleStack                                                                      
                                ).First()                                 
                                      )                
                                orderby ms.Lgv.Station.Positions
                                select ms.Lgv.Station.Positions
                                
                                ).FirstOrDefault();

Open in new window


I need to get the single pallet two if is Stackable.

Please see the picture for better explanation.

Thank you
LinqMatrix.png
0
iscivanomar
Asked:
iscivanomar
  • 2
1 Solution
 
Srinivasulu MuppalaLead DeveloperCommented:
break the linq into two iterations such as  break your first iteration upto
.....Positions return it positions and

apply linq again on the result positions.matrix

.Select(y =>  y.TrackingId > 0
                                                                    && y.TrackingInfo.StackableType > 0
                                                                    && y.TrackingInfo.StackableType == (int)EStackableType.doubleStack
                                                                    && y.TrackingInfo.StackableType != (int)EStackableType.singleStack                                                                      
                                )
include the empty check with above specified checks otherwise if second element is stackable(empty) same issue will come
0
 
iscivanomarAuthor Commented:
Hello srinipro,
           sorry to get back to you until today. I went to other project for two days.  
I breaked down to this:

 var stackable = (from ms in Model.CurrentMissions
                                    where (ms.CurrentStationId == StationId)
                                    orderby ms.Lgv.Station.Positions
                                    select ms.Lgv.Station.Positions).FirstOrDefault();

                var stackableUDC = (from st in stackable
                                     where (st.TrackingInfo != null
                                            && st.TrackingInfo.TrackingId > 0
                                            && st.TrackingInfo.StackableType > 0
                                            && st.TrackingInfo.StackableType == (int)EStackableType.doubleStack
                                            && st.TrackingInfo.StackableType != (int)EStackableType.singleStack)
                                     orderby st.TrackingInfo.TrackingId
                                     select st.TrackingInfo.TrackingId
                                    ).FirstOrDefault();

Open in new window


however, I am getting an error called:  
failed to compare two elements in the array in the second LINQ.
I am not using IComparable. what does this mean?

Thank you
0
 
iscivanomarAuthor Commented:
Hello srinipro,
       I break the LINQ SQL as you said and it work. I was able to check and compare the data more easily. Thank you again and have a good day.
0

Featured Post

What does it mean to be "Always On"?

Is your cloud always on? With an Always On cloud you won't have to worry about downtime for maintenance or software application code updates, ensuring that your bottom line isn't affected.

  • 2
Tackle projects and never again get stuck behind a technical roadblock.
Join Now