splitting octets with awk

I  have a ip address  Quad=10.20.30.40

with awk I want to print this out
10
20
30
40

awk -F.     is not working for me.
TIMFOX123Asked:
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ozoCommented:
Quad=10.20.30.40
echo $Quad | awk -F. '{for( i=1;i<=NF; ++i){ print $i}}'
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farzanjCommented:
Works for me
echo 10.20.30.40 | awk -F. '{print $1"\n"$2"\n"$3"\n"$4}'
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woolmilkporcCommented:
Did you try this?

awk -F\. '{print $1 "\n" $2 "\n" $3 "\n" $4}
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arnoldCommented:
echo QUAD | awk -F\. ' (NF == 4  { print $1"\n"$2"\n"$3"\n"$4"\n" } '

NF is the equal to the number of elements. If there are not the four octets, there will be no output.

. ' " , etc. have to be escaped (\) when those are the delimeter.
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TintinCommented:
Do you have to use awk?

If not, easier to do

echo 10.20.30.40|tr '.' '\n'

Open in new window

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TIMFOX123Author Commented:
Everybody did such a great job

ozo has the answer I used.

tintin, your answer just rocks !!
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