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PHP Counting issue, only want it to count as 1, even if there are more values.

Posted on 2013-01-25
2
164 Views
Last Modified: 2013-03-12
Good afternoon experts.

I'm trying to count different Misdemeanor and Felony charges in our jail system.  When someone is booked in jail, they are given a booking number, that booking number may have multiple charges associated with it.  If all the charges are Misdemeanor, then I want to count 1 misd count, if there are multiple misd and one felony charge in that booking, then that booking should count as a felony booking.

My current code that is counting each "CHARGE" separately (which is not desired) is below

	$sql3 = "select * from jms_03mast where jm3_booking_num = '".$row['jm1_active_booking']."'";
		$result3 = $myConn->query($sql3);
		while($row3 =& $result3->fetchRow(DB_FETCHMODE_ASSOC))
		{
			//this is a total count, per charge, could have multiple per booking....
			if($row3['jm3_felony'] == 'F' || $row3['jm3_felony'] == 'Y')
			{
				$felony++;
			}
			if($row3['jm3_felony'] == 'M' || $row3['jm3_felony'] == 'N')
			{
				$misd++;
			}
			else
			{
				$othermf++;
			}
		
		}
			

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As you can see i'm looping through a charge table (jms_03mast) and counting each charge per booking... I'm not sure how I would do this and only get 1 count per booking...

As a quick example:

Booking#   Charge#   Felony/misd:
01               01            M
01               02            M
01               03            M
02               01            M
02               02            F

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So in the above example, I would have a total count of '2' bookings and 1 felony booking (since booking 02 has a felony charge entered) and 1 misd booking.

I hope I have explained this well enough, its been giving me a headache trying to figure it out!

Thank you!
0
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Question by:hej613
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2 Comments
 
LVL 31

Accepted Solution

by:
Marco Gasi earned 500 total points
ID: 38820369
You can try this untested code. I assumed in your table the column which holds the booking id is called 'booking' (as in the table you posted above) so you have to update this value accordingly to your table column name for booking id

<?php
//SET A DEFAULT VALUE FOR BOOKING
$booking = "00";
$sql3 = "select * from jms_03mast where jm3_booking_num = '".$row['jm1_active_booking']."'";
		$result3 = $myConn->query($sql3);
		while($row3 =& $result3->fetchRow(DB_FETCHMODE_ASSOC))
		{
			//CHECK IF THE BOOKING IS THE SAME: IF NOT, WE UPDATE BOOKING ID FLAG
			if ($row['booking'] != $booking) $booking = $row['booking'];
			//this is a total count, per charge, could have multiple per booking....
			if($row3['jm3_felony'] == 'F' || $row3['jm3_felony'] == 'Y' && $row['booking'] == $booking)
			{
				$felony++;
			}
			if($row3['jm3_felony'] == 'M' || $row3['jm3_felony'] == 'N' && $row['booking'] == $booking)
			{
				$misd++;
			}
			else
			{
				$othermf++;
			}
		
		}
			
                                  

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Cheers
0
 
LVL 110

Expert Comment

by:Ray Paseur
ID: 38822251
Please post the CREATE TABLE statement for this table.  Armed with that we may be able to give you some tested and working demonstration code.

My first guess is that you can GROUP BY the booking and ORDER BY felony/misd.  If the first row contains felony, you've got your answer (I think).  My second guess is that you would want to get a DBA involved to normalize your data base tables.
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