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PHP IF statement

Posted on 2013-01-25
2
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Last Modified: 2013-01-25
I have text on a page.
Menuhead found <?php $num?> Results

I am trying to do an if statement with formating and the number of results included.  So if its one resukt the word would be result and if it zero or many it would be results.

<?php
if ($num === 1)
	{
   echo <h2 align="left">MENUHEAD FOUND 1 RESULT</h2>;
   }
 else
   {
   echo <h2 align="left">MENUHEAD FOUND <?php echo $num ?> RESULTS</h2>;
   }
   ?>

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This however is fraught with errors.
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Question by:DS928
2 Comments
 
LVL 31

Accepted Solution

by:
Frosty555 earned 500 total points
ID: 38821362
Your overall logic is correct, but the problem you are having is that there are a number of syntactical errors in your code. Your strings in the echo statements are not enclosed in doublequotes. Even if they were, you are not escaping the doublequotes in the [align="left"] part of the string for your H2 tags, and finally you have a redundant "<?php" opening tag.

Try this instead:

<?php
if ($num == 1) {
    echo "<h2 align=\"left\">MENUHEAD FOUND 1 RESULT</h2>";
} else {
    echo "<h2 align=\"left\">MENUHEAD FOUND " . $num . " RESULTS</h2>";
}
?>

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Read up on this page for how to do escaping of characters in PHP strings:

http://php.net/manual/en/language.types.string.php
0
 

Author Closing Comment

by:DS928
ID: 38821370
I would have been here all night trying to figure this one out!  Works perfectly!  Also thank you for the link.  It really helps!
0

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