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Image rotator... jQuery

I have the following code to rotate four photos; but it doesn't rotate them.

Question: How can I change this code so that it will fade in next picture and hide the current one?

Thank you.
<!DOCTYPE html>
  <html>
    <head>

	<title>iQuery CSS sizing and positioning</title>
	<script type="text/javascript" src="jQuery/jquery-1.3.2.js"></script>
	<script type="text/javascript">
		//$("document").ready(function() {
		  	$(function() {
				setInterval("rotateImages()",2000);
			});
			function rotateImages() {
				var oCurPhoto = $("#photoShow div.current");
				var oNxtPhoto = oCurPhoto.next();
				if (oNxtPhoto.length == 0)
					oNxtPhoto = $("#photoShow div.first");
					
				oCurPhoto.removeClass('current').addClass('previous');
				oNxtPhoto.css({opacity: 0.0}).addClass('current').animate({opacity: 1.0}, 1000, 
					function() {
						oCurPhoto.removeClass('previous');
					});
			}

		//});
	</script>
	<style type="text/css">
		#photoShow { 
			height: 400px;
			width:  400px;
		}
		#photoShow div {
			position: absolute;
			z-index: 0;
		}
		#photoShow div.previous {
			z-index: 1;
		}
		#photoShow div.current {
			z-index: 2;
		}
		p{font-size: 26pt;}
	</style>
	</head>
	<body>
	  <p>jQuery-based Image Rotator</p>
		<div id="photoShow">
			<div id="current">
				<img class="gallery" src="images/Grass.jpg" alt="Photo Gallery" width="400" height="400" /img>
			</div>
			<div>
				<img class="gallery" src="images/leaf.jpg" alt="Photo Gallery" width="400" height="400" /img>
			</div>
			<div>
				<img class="gallery" src="images/Spring.jpg" alt="Photo Gallery" width="400" height="400" /img>
			</div>
			<div>
				<img class="gallery" src="images/Water.jpg" alt="Photo Gallery" width="400" height="400" /img>
			</div>
		</div><!-- photoShow -->
	</body>
</html>

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Grass.jpg
Leaf.jpg
Spring.jpg
Water.jpg
0
Mike Eghtebas
Asked:
Mike Eghtebas
1 Solution
 
Robert SchuttSoftware EngineerCommented:
in the html, change
<div id="current">

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to
<div class="current first">

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(edited)
0
 
Mike EghtebasDatabase and Application DeveloperAuthor Commented:
Thank you.
0

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