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  • Priority: Medium
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Sort JavaScript output

This code works great, thanks to Slick812. But I need the output sorted by the number of times the duplicate string is found, in descending order.

Also prefer to list just the first 10 matches but that is not as important as the sort.
<!DOCTYPE html>
<html>
<head>
  
  <style type='text/css'>
		
	}
  body,td,th {
	font-family: Verdana, Arial, Helvetica, sans-serif;
	font-size: 12px;
	color: #000000;
}
body {
	background-color: #FFFFFF;
}
</style>

</head>
<body>




<script>
var tx1 = "Bobob is attempting-to find him the reason, Janet is attempting. to understand Bobob and to! reason with him a!s Bobob in reason or reason.";

function getDups(txt) { // Only has duplicates
// I had to remove most common punctuation
// BUT not every one, so BeWare if the text has other punctuation
txt=txt.replace(/,/g,"");
txt=txt.replace(/\./g,"");
txt=txt.replace(/\?/g,"");
txt=txt.replace(/!/g,"");
txt=txt.replace(/\"/g,"");
txt=txt.replace(/\'/g,"");
txt=txt.replace(/\-/g," ");
txt=txt.replace(/;/g,"");
txt=txt.replace(/:/g," ");

wordary = txt.split(' ');
wordary = wordary.sort();

var dNum = 1;
var dups = {};
for (var i=0; i < wordary.length-2; i++) {
if ( wordary[i].length > 4 
    && wordary[i+1].length > 4 
    && wordary[i+1] == wordary[i]) {
	++dNum;
	dups[wordary[i]] = dNum;
	} else dNum = 1;
}

txt = "";
var key = "";
for (key in dups) {
    txt+= key +" "+dups[key]+"<br />";
    }
return txt;
}


function showUm(text) {
text = getDups(text);
document.getElementById("de").innerHTML = text;
}

</script> 


<button onClick="showUm(tx1)"> Get Duplicates </button>
<p id="de"> </p> 

  
</body>
</html> 

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0
Qsorb
Asked:
Qsorb
  • 3
  • 2
2 Solutions
 
leakim971PluritechnicianCommented:
test page : http://jsfiddle.net/LNDsY/2/
var tx1 = "Bobob is attempting-to find him the reason, Janet is attempting. to understand Bobob and to! reason with him a!s Bobob in reason or reason.";

function getDups(txt) { // Only has duplicates
    // I had to remove most common punctuation
    // BUT not every one, so BeWare if the text has other punctuation
    txt=txt.replace(/,/g,"");
    txt=txt.replace(/\./g,"");
    txt=txt.replace(/\?/g,"");
    txt=txt.replace(/!/g,"");
    txt=txt.replace(/\"/g,"");
    txt=txt.replace(/\'/g,"");
    txt=txt.replace(/\-/g," ");
    txt=txt.replace(/;/g,"");
    txt=txt.replace(/:/g," ");
    
    wordary = txt.split(' ');
    wordary = wordary.sort();
    
    var dNum = 1;
    var dups = {};
    for (var i=0; i < wordary.length-2; i++) {
    	if ( wordary[i].length > 4 
            && wordary[i+1].length > 4 
            && wordary[i+1] == wordary[i]) {
            ++dNum;
            dups[wordary[i]] = dNum;
        } else dNum = 1;
    }

	// CONVERT "HASH TABLE" TO ARRAY BECAUSE WE CAN'T SORT "HASH TABLE"
    var arr = [];
    for(var k in dups) {
        var obj = {}; // silly notation
        obj[k] = dups[k];
        arr.push(obj);
    }
  
    // SORT ARRAY
    arr.sort(function(d1,d2) {
        for(key1 in d1) break;
        for(key2 in d2) break;
        return d2[key2]-d1[key1];
    })
    
    txt = "";
    for(var i=0;i<arr.length;i++) {
        for(var k in arr[i]) break;
        txt+= k +" "+arr[i][k]+"<br />";
    }
    return txt;
}


function showUm(text) {
    text = getDups(text);
    document.getElementById("de").innerHTML = text;
}

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0
 
Slick812Commented:
here a function that does what you ask, but did not test it much, so may get bogged down with lengthy text inputs?

<script>
var tx1 = "Bobob attempting-to finds the finds (reason), finds att;empting. finds yoodol yoodol understand Bobob finds! reason finds Bobob? finds reason reason. ";
tx1 += "lengt hight money split lengt lower lengt hight hight:split other! hight hight split lower lower money. other yoodol uuuuu uuuuu"


function getDups(txt) {
txt=txt.replace(/[)(;,!\.\?]/g,"");
txt=txt.replace(/[:\-]/g," ");

wordary = txt.split(' ');
wordary = wordary.sort();

var dNum = 1, dups = {};
for (var i=0; i < wordary.length-2; i++) {
if ( wordary[i].length > 4 
    && wordary[i+1].length > 4 
    && wordary[i+1] == wordary[i]) {
	++dNum;
	dups[wordary[i]] = dNum;
	} else dNum = 1;
}
var key = "", pos = [];
wordary = [];
for (key in dups) {
	pos.push(key);
	wordary.push(dups[key]);
    }

var b = 0, a = wordary.length-1;;
while (b < a) {
for (i = b; i < a; i++) {
if (wordary[i] < wordary[a]) {dNum =wordary[i]; key = pos[i];
    wordary[i] = wordary[a]; pos[i] = pos[a];
    wordary[a] = dNum; pos[a] = key;
    }
}
--a;
}

txt = "";
dNum = wordary.length;
if (dNum > 10) dNum = 10;
for (i=0; i < dNum; i++) {

// CHANGE THIS HTML BELOW TO YOUR OUTPUT STYLE or LINE BREAKS
txt+= wordary[i]+" duplicates for<br/>. . <b>"+pos[i] +"</b><br />";
//txt+= "<b>"+pos[i] +"</b><br />. . has "+wordary[i]+" duplicates,<br />";
}
return txt;
}

function showUm(text) {
text = getDups(text);
document.getElementById("de").innerHTML = text;
}
</script>

Open in new window


Be sure to change the HTML to your specs on this line -

// CHANGE THIS HTML BELOW TO YOUR OUTPUT STYLE or LINE BREAKS
txt+= wordary+" duplicates for<br/>. . <b>"+pos +"</b><br />";

where wordary has the number and  pos  has the WORD
0
 
QsorbAuthor Commented:
leakim971 was first so he get's half the points because Slick812 gave me both, he also set the amount of the results shown to ten, so I'm awarding points equally.

Thanks guys for the quick and excellent work and no confusion.
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leakim971PluritechnicianCommented:
150
350

Equally?
0
 
QsorbAuthor Commented:
Sorry, that should have been equally. Not sure what happened.  How do I ask the moderator or whomever controls the points to divvy them equally?
0
 
leakim971PluritechnicianCommented:
no, of course :))
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