• Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 172
  • Last Modified:

show distinct value

I have an elaborate SQL string below that calculates the number or days in my attendance grid that had activity in it. In the output it shows several records of the committee.  How can I show Distinct Committees in the output?


SELECT committee,Activity, COUNT([Last Name]) as Participants,
CASE WHEN SUM( [1]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [2]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [3]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [4]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [5]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [6]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [7]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [8]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [9]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [10]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [11]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [12]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [13]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [14]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [15]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [16]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [17]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [18]) > 0 THEN 1 ELSE 0 END + 
CASE WHEN SUM( [19]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [20]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [21]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [22]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [23]) > 0 THEN 1 ELSE 0 END +    CASE WHEN SUM( [24]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [25]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [26]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [27]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [28]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [29]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM( [30]) > 0 THEN 1 ELSE 0 END + CASE WHEN SUM([31]) > 0 THEN 1 ELSE 0 END AS #Days_With_Activity
FROM AttendanceGrid
where 7 <= datediff(year, Age , EntryTime) And Fiscal = 2013 and Total > 0 and not Committee like 'ivpa%' and Month IN ('July', 'August', 'September', 'October', 'November','December')
GROUP BY activity, Committee order by Committee

Open in new window

0
al4629740
Asked:
al4629740
1 Solution
 
topdog770Commented:
Hi Al,

Here's a good link that should point you in the right direction.

http://blog.sqlauthority.com/2012/07/27/sql-server-query-to-get-unique-distinct-data-based-on-condition-eleminate-duplicate-data-from-resultset/

If you post the table schema, some sample data and indicate what level of distinction you are wanting, I can help you more.

And determining this one detail, may help you find your own answer.  What makes the data distinct?  

Regards,

Michael
0
 
Guy Hengel [angelIII / a3]Billing EngineerCommented:
you have to remove Activity from the SELECT and the GROUP BY part.

see also this article for explanations:
http://www.experts-exchange.com/Database/Miscellaneous/A_3203-DISTINCT-vs-GROUP-BY-and-why-does-it-not-work-for-my-query.html
0

Featured Post

Free Tool: Subnet Calculator

The subnet calculator helps you design networks by taking an IP address and network mask and returning information such as network, broadcast address, and host range.

One of a set of tools we're offering as a way of saying thank you for being a part of the community.

Tackle projects and never again get stuck behind a technical roadblock.
Join Now