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Split comma separated values in column

I have a column in a table that can have anywhere from 1 to 6 comma separated values:
column1 = value1,value2, value3, etc

I need to parse that column so that the resulting select returns a row with a single column for each delimited value.

Thanks in advance!
0
Rickzzz
Asked:
Rickzzz
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2 Solutions
 
appariCommented:
try like this,
create a UDF
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO

CREATE FUNCTION [dbo].[GetListFromCSVString]
(		
	@csvString varchar(500), 
	@sep varchar(1)
)
RETURNS @ValueList TABLE 
(
	ID int,
	FldVal varchar(50)
)
AS
begin
	declare @curPos int
	declare @prevCurPos int
	declare @ID int

	set @ID=1
	set @curPos = -1
	set @prevCurPos = 1
	
	While @curPos <>0
	begin
		set @curPos = charindex(@sep, @csvString, @curPos + 1)
		if @curPos <> 0 
		begin
			insert into @ValueList values( @ID, substring(@csvString, @prevCurPos, @curPos-@prevCurPos) )
		end
		else
		begin
			insert into @ValueList values(@ID, substring(@csvString, @prevCurPos, len(@csvString)-@prevCurPos +1) )
		end
		Set @ID= @ID+1
		Set @prevCurPos = @curPos+1
	end
	return 

End 

Open in new window


use it your SQL as follows

-- use with CSV string as parameter
select * from  [dbo].[GetListFromCSVString]('Test1,Test2',',')

-- use with CSV values from a table
select  yourtableName.*  , A.FldVal from  yourtableName
outer apply [dbo].[GetListFromCSVString]( yourtableName.csvFieldName ,',') A
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ValentinoVBI ConsultantCommented:
Here's a method without using a custom function:

declare @theString varchar(100) = 'value1,value2,value3,last value';
declare @delimiter varchar(10) = ',';

with TheData as ( select @theString StrVal)
, StrToCols as (
	select ltrim(SUBSTRING(@theString, number
			, CHARINDEX(@delimiter, D.StrVal + @delimiter,number) - number)) AS val
		, ROW_NUMBER() over (order by N.number) as ID
	FROM TheData D
	CROSS JOIN (SELECT number FROM master..spt_values with (nolock) WHERE type = 'P') AS N
	WHERE SUBSTRING(@delimiter + D.StrVal, number, 1) = @delimiter
		AND number < LEN(D.StrVal) + 1
)
select *
from StrToCols
pivot (min(val) for ID in ([1], [2], [3], [4], [5], [6])) as pvt

Open in new window

For info on what I'm doing here, I'd like to refer you to the following article by our expert mark_wills: Fun with MS SQL spt_values for delimited strings and virtual calendars

I'm using his method to split the string, then I use the ROW_NUMBER function to add an incrementing identifier to the values and finally I use the PIVOT operator to make columns out of the rows.
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RickzzzAuthor Commented:
Thanks guys.

Appari, I created the UDF and I get this:
"Msg 102, Level 15, State 1, Line 7 Incorrect syntax near 'auto'."

when I run:
select
	[auto].*
	,a.FldVal
from 
	[auto]
		outer apply
			dbo.GetListFromCSVString([auto].vehicleList,',') a  

Open in new window


Do you see anything wrong here?  Thanks!
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appariCommented:
what happens if you run the following sql? are you getting the splitted values?

select * from  [dbo].[GetListFromCSVString]('Test1,Test2',',')
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RickzzzAuthor Commented:
That returns:

ID      FldVal
1      Test1
2      Test2

Thanks.
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appariCommented:
i dont see any problem with the SQL you were executing. try this

select      A.*
      ,B.FldVal
from  [auto] A  outer apply dbo.GetListFromCSVString(A.vehicleList,',') B
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RickzzzAuthor Commented:
Msg 102, Level 15, State 1, Line 3
Incorrect syntax near '.'.

I had a similar issue running a udf from another post. Might just be a default env setting or something on my end jacking things up.

Anyway, like the other post, your certs and points on this site pretty much dictate your stuff is more than sound. Looks like I'll have to Google for the obscure reason I can't execute the thing. Something to do with the table name [Auto] maybe?

I'll go ahead and mark this as the answer, again, given your status here. Thanks for the extra effort though.
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appariCommented:
what is your sqlserver version?
0
 
RickzzzAuthor Commented:
2012.

Rick
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ValentinoVBI ConsultantCommented:
Hi Rick, did you give my proposal a try as well?
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RickzzzAuthor Commented:
Not yet Valentino, my head wants to explode when I try to make sense of it. But I'm going to. Thanks.
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ValentinoVBI ConsultantCommented:
Heh, I understand :)

If you have any questions on that solution, don't hesitate to ask!

In short, all you need to do is replace this:

select @theString StrVal

with your query that retrieves the column with the comma-separated values.  It should run fine, you'll always get six columns back.  In case your column contains less than six values, let's say four, the last two columns that get generated will be null.

To get a good understanding of it, try it out with a couple of examples first, like I did in my proposal.
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